描述：

用 sym()  生成了 矩阵；           再用 solve()   结果返回 结构体，还带sym 型。。。

尝试：

用 struct 转换         ;      eval()     什么的 都无解，，  (结构体还带sym。。。。昏了)

求：

怎么    批量    引用，查看生成的解。。。。。。。？  最好整成double型的 。如果是     for()      就免了吧

代码备注：

E 是一个 关于  P中元素的 方程组

。。。

。。。

P=sym('P',[3 b]);

solve(E,'Real',true);

。。。

。。。

P =

P1_1: [1x1 sym]

P1_2: [1x1 sym]

P1_3: [1x1 sym]

P1_4: [1x1 sym]

P1_5: [1x1 sym]

P1_6: [1x1 sym]

P1_7: [1x1 sym]

P1_8: [1x1 sym]

P1_9: [1x1 sym]

P2_1: [1x1 sym]

P2_2: [1x1 sym]

P2_3: [1x1 sym]

P2_4: [1x1 sym]

P2_5: [1x1 sym]

P2_6: [1x1 sym]

P2_7: [1x1 sym]

P2_8: [1x1 sym]

P2_9: [1x1 sym]

P3_1: [1x1 sym]

P3_2: [1x1 sym]

P3_3: [1x1 sym]

P3_4: [1x1 sym]

P3_5: [1x1 sym]

P3_6: [1x1 sym]

P3_7: [1x1 sym]

P3_8: [1x1 sym]

P3_9: [1x1 sym]

P1_10: [1x1 sym]

P1_11: [1x1 sym]

P1_12: [1x1 sym]

P1_14: [1x1 sym]

P1_15: [1x1 sym]

P1_16: [1x1 sym]

P1_17: [1x1 sym]

P1_18: [1x1 sym]

P1_19: [1x1 sym]

P1_20: [1x1 sym]

P1_21: [1x1 sym]

P1_22: [1x1 sym]

P1_23: [1x1 sym]

P1_24: [1x1 sym]

P1_25: [1x1 sym]

P2_10: [1x1 sym]

P2_11: [1x1 sym]

P2_12: [1x1 sym]

P2_14: [1x1 sym]

P2_15: [1x1 sym]

P2_16: [1x1 sym]

P2_17: [1x1 sym]

P2_18: [1x1 sym]

P2_19: [1x1 sym]

P2_20: [1x1 sym]

P2_21: [1x1 sym]

P2_22: [1x1 sym]

P2_23: [1x1 sym]

P2_24: [1x1 sym]

P2_25: [1x1 sym]

P3_10: [1x1 sym]

P3_11: [1x1 sym]

P3_12: [1x1 sym]

P3_14: [1x1 sym]

P3_15: [1x1 sym]

P3_16: [1x1 sym]

P3_17: [1x1 sym]

P3_18: [1x1 sym]

P3_19: [1x1 sym]

P3_20: [1x1 sym]

P3_21: [1x1 sym]

P3_22: [1x1 sym]

P3_23: [1x1 sym]

P3_24: [1x1 sym]

P3_25: [1x1 sym]