php 鼠标小手,鼠标移动至少一次时创建PHP会话(Create PHP session when mouse moved at least once)...

鼠标移动至少一次时创建PHP会话(Create PHP session when mouse moved at least once)

我想在鼠标移动至少一次时创建php会话，如果鼠标继续移动则不需要做任何事情

我正在使用此代码，但它没有解决要求

jQuery(document).ready(function()

{

$(document).mousemove(function(e)

{

$('#status').html(e.pageX);

$('#status1').html(e.pageY);

$.ajax({

type: 'POST',

url: 'second.php',

data: {

'x': '10',

'y': '20'

success: function(msg){

//what you want after request

}

});

I want to create php session when mouse is moved at least once then no need to do anything if mouse keeps moving

I am using this code but its not solving the requirement

jQuery(document).ready(function()

{

$(document).mousemove(function(e)

{

$('#status').html(e.pageX);

$('#status1').html(e.pageY);

$.ajax({

type: 'POST',

url: 'second.php',

data: {

'x': '10',

'y': '20'

success: function(msg){

//what you want after request

}

});

原文：https://stackoverflow.com/questions/47845256

更新时间：2020-01-28 06:34

最满意答案

PHP代码应该是这样的：

session_start();

if (!isset($_SESSION['mouseMoved'])

$_SESSION['mouseMoved'] = "whatever you want";

此外，您应该在JS中设置一些变量，以便仅将请求发送到服务器一次。

The PHP code should be something like this:

session_start();

if (!isset($_SESSION['mouseMoved'])

$_SESSION['mouseMoved'] = "whatever you want";

Also, you should set some variable in JS so that the request is only sent to the server once.

2017-12-17

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