部分原创
| 66下一步 | Vs 堆栈 理论修改的上限是多少 ？
问题2： 全局变量去 最大的上限是多少？
堆栈（休养版本测试）
2012年3月31日17:31:27 3月
|
从 10^5到 10^6数组，导致vs…
当前：搭好脚手架。
改进： 修改vs系数。（byte 为单位i）
改进二： 细化 时间粒度。
以上是我在项目汇总的修改。下面是阅读笔记
test dword ptr [eax],eax ; probe page.
2010年05月18日 星期二 20:19
局部数组变量定义超过所分配的最大空间
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Posts Tagged 变量
局部数组变量定义所分配的最大空间为多少?如何设置大小
有两个程序
A：
- #include "stdafx.h"
- int _tmain(int argc, _TCHAR* argv[])
- {
- int nArray[256000] = {0};
- nArray[1] = 5;
- printf("array 1 is %d",nArray[1]);
- return 0;
- }
B：
- #include "stdafx.h"
- int _tmain(int argc, _TCHAR* argv[])
- {
-
int nArray[260000] = {0};
//66 大于 1m了
- nArray[1] = 5;
- printf("array 1 is %d",nArray[1]);
- return 0;
- }
大家通过运行可以发现，A是可以正常运行的，B虽然编译通过了，可是当运行时就会弹出错误
错误的原因，就是栈溢出
局部变量的申请空间是存放于栈中，windows里默认栈内存是1M
所以当申请空间大于1M时就会出现溢出错误
通过debug就会进入以下文件chkask.asm
page ,132
title chkstk – C stack checking routine
;***
;chkstk.asm – C stack checking routine
;
; Copyright (c) Microsoft Corporation. All rights reserved.
;
;Purpose:
; Provides support for automatic stack checking in C procedures
; when stack checking is enabled.
;
;*******************************************************************************
.xlist
include cruntime.inc
.list
; size of a page of memory
_PAGESIZE_ equ 1000h
CODESEG
page
;***
;_chkstk – check stack upon procedure entry
;
;Purpose:
; Provide stack checking on procedure entry. Method is to simply probe
; each page of memory required for the stack in descending order. This
; causes the necessary pages of memory to be allocated via the guard
; page scheme, if possible. In the event of failure, the OS raises the
; _XCPT_UNABLE_TO_GROW_STACK exception.
;
; NOTE: Currently, the (EAX < _PAGESIZE_) code path falls through
; to the "lastpage" label of the (EAX >= _PAGESIZE_) code path. This
; is small; a minor speed optimization would be to special case
; this up top. This would avoid the painful save/restore of
; ecx and would shorten the code path by 4-6 instructions.
;
;Entry:
; EAX = size of local frame
;
;Exit:
; ESP = new stackframe, if successful
;
;Uses:
; EAX
;
;Exceptions:
; _XCPT_GUARD_PAGE_VIOLATION – May be raised on a page probe. NEVER TRAP
; THIS!!!! It is used by the OS to grow the
; stack on demand.
; _XCPT_UNABLE_TO_GROW_STACK – The stack cannot be grown. More precisely,
; the attempt by the OS memory manager to
; allocate another guard page in response
; to a _XCPT_GUARD_PAGE_VIOLATION has
; failed.
;
;*******************************************************************************
public _alloca_probe
_chkstk proc
_alloca_probe = _chkstk
push ecx
; Calculate new TOS.
lea ecx, [esp] + 8 – 4 ; TOS before entering function + size for ret value
sub ecx, eax ; new TOS
; Handle allocation size that results in wraparound.
; Wraparound will result in StackOverflow exception.
sbb eax, eax ; 0 if CF==0, ~0 if CF==1
not eax ; ~0 if TOS did not wrapped around, 0 otherwise
and ecx, eax ; set to 0 if wraparound
mov eax, esp ; current TOS
and eax, not ( _PAGESIZE_ – 1) ; Round down to current page boundary
cs10:
cmp ecx, eax ; Is new TOS
jb short cs20 ; in probed page?
mov eax, ecx ; yes.
pop ecx
xchg esp, eax ; update esp
mov eax, dword ptr [eax] ; get return address
mov dword ptr [esp], eax ; and put it at new TOS
ret
; Find next lower page and probe
cs20:
sub eax, _PAGESIZE_ ; decrease by PAGESIZE
| test dword ptr [eax],eax ; probe page. |
|
jmp short cs10
_chkstk endp
end
提示栈溢出
所以解决此问题的方法就是扩大栈空间的大小
方法为
项目->属性->链接器->系统->堆栈保留大小
注：这里填的是字节数
如果你想把他扩大为2M的话，
1024*1024*2 = 2097152
然后再编译运行的话A,B就都可以通过了
源文档 <http://hi.baidu.com/linzch/blog/item/e5107ff0a6cf6ccf7831aa02.html>
