我认为您可能缺少的是确切地知道您希望分配结构内存的位置。下面的c代码提供了一个为struct分配内存并返回指向它的指针的函数（new_struct（））。#include

#include

#include

typedef struct {

int a;

int b;

} my_struct;

my_struct *new_struct()

{

my_struct *struct_instance = (my_struct *)malloc(sizeof(my_struct));

memset(struct_instance, 0, sizeof(my_struct));

return struct_instance;

}

int modify_struct(my_struct *ms) {

ms->a = 1;

ms->b = 2;

return 0;

}

void print_struct_c(my_struct *ms) {

printf("my_struct {\n"

" a = %d\n"

" b = %d\n"

"}\n", ms->a, ms->b);

}

从Python获取指针，调用执行分配的C函数，然后可以将其传递给将其作为参数的其他C函数。import ctypes

lib_file_path = <<< path to lib file >>>

# Very simple example of how to declare a ctypes structure to twin the

# C library's declaration. This doesn't need to be declared if the Python

# code isn't going to need access to the struct's data members.

class MyStruct(ctypes.Structure):

_fields_ = [('a', ctypes.c_int),

('b', ctypes.c_int)]

def print_struct(s):

# Print struct that was allocated via Python ctypes.

print("my_struct.a = %d, my_struct.b = %d" % (s.a, s.b))

def print_struct_ptr(sptr):

# Print pointer to struct. Note the data members of the pointer are

# accessed via 'contents'.

print("my_struct_ptr.contents.a = %d, my_struct_ptr.contents.b = %d"

% (sptr.contents.a, sptr.contents.b))

my_c_lib = ctypes.cdll.LoadLibrary(lib_file_path)

# If you don't need to access the struct's data members from Python, then

# it's not necessary to declare MyStruct above. Also, in that case,

# 'restype' and 'argtypes' (below) can be set to ctypes.c_void_p instead.

my_c_lib.new_struct.restype = ctypes.POINTER(MyStruct)

my_c_lib.modify_struct.argtypes = [ctypes.POINTER(MyStruct)]

# Call C function to create struct instance.

my_struct_c_ptr = my_c_lib.new_struct()

print_struct_ptr(my_struct_c_ptr)

my_c_lib.modify_struct(my_struct_c_ptr)

print_struct_ptr(my_struct_c_ptr)

# Allocating struct instance from Python, then passing to C function.

my_struct_py = MyStruct(0, 0)

print_struct(my_struct_py)

my_c_lib.modify_struct(ctypes.byref(my_struct_py))

print_struct(my_struct_py)

# Data members of Python allocated struct can be acessed directly.

my_struct_py.a = 555

my_c_lib.print_struct_c(ctypes.byref(my_struct_py)) # Note use of 'byref()'

# to invoke c function.

上面的代码已经更新，包括如何通过Python分配结构实例的示例，以及如何访问C已分配或Python分配结构的数据成员（请注意打印函数中的差异）。