一、背景

在以下数据中如何实现对每一个列按照更新时间取最新的非null值？

1   a      a      null  202301     202301
1   b      b      null  null       202302
1   null   c      null  null       202303
1   d      null   null  null       202304如何实现 1  d   c  null  202301   202301

二、last_value函数的使用

select last_value(age) over(partition by a order by b,c desc)

SELECT id,last_value(name,TRUE)    OVER (PARTITION BY id) name,last_value(age,TRUE)     OVER (PARTITION BY id) name,last_value(address,TRUE) OVER (PARTITION BY id) address,last_value(ct_time,TRUE) OVER (PARTITION BY id) ct_time,up_time
FROM 
(select *
from
(select 1 as id,'a' as name ,'a' as age,null as address,202301 as ct_time,202301 as up_time
union all
select 1 as id,'b' as name ,'b'  as age,null as address,null as ct_time,  202302 as up_time
union all
select 1 as id,null as name,'c'  as age,null as address,null as ct_time,  202303 as up_time
union all
select 1 as id,'d' as name ,null as age,null as address,null as ct_time,  202304 as up_time
) t
ORDER BY t.up_time asc
)；
在上述sql中，使用last_value函数对每一个列按照主键id分组，取一个最新值，如果遇见null值，使用参数true进行忽略，最后再使用窗口函数row_number进行分组排序取最大一条数据即可实现数据合并。