如图：实现表单输入密码和确认密码的时候进行表单校验。
实现方式：
1.在代码的data里面定义，函数验证的方法。如图所示,代码如下
【代码】如下：
const validatePassword = (rule, value, callback) => {if (value === '') {callback(new Error('请输入密码'));} else {let yz = 0;this.passwordPercent = 0;//6-20位包含字符、数字和特殊字符if (this.form1.newPassword.length < 11) {callback(new Error("长度在 11 到 20 个字符"));}if (this.form1.newPassword.match(/([a-z])+/)) {yz++;}if (this.form1.newPassword.match(/([0-9])+/)) {yz++;}if (this.form1.newPassword.match(/([A-Z])+/)) {yz++;}if (this.form1.newPassword.match(/([\W_])+/)) {yz++;}if (yz < 2) {callback(new Error("密码必须是大小写字母、数字、特殊符号两种及以上组成"));}switch (yz) {case 0: this.passwordPercent = 0; callback();case 1: this.passwordPercent = 25; callback();case 2: this.passwordPercent = 50; callback();case 3: this.passwordPercent = 75; callback();case 4: this.passwordPercent = 100; callback();}}};const equalToPassword = (rule, value, callback) => {if (this.form1.newPassword !== value) {callback(new Error("两次输入的密码不一致"));} else {callback();}};2.设置表单校验的rule。 rule在return函数里面。名称可以自己定义。作为变量使用。
rules1: {selectApps: [{ required: true, message: "请选择应用系统", trigger: "blur" }],newPassword: [{ required: true, message: "新密码不能为空", trigger: "blur" },{ min: 8, max: 20, validator: validatePassword, trigger: "blur" }],confirmPassword: [{ required: true, message: "确认密码不能为空", trigger: "blur" },{ required: true, validator: equalToPassword, trigger: "blur" }]},3.给表单添加rule。 则表单输入会按照规则进行校验。:rules="rules1"
rules1就是步骤二定义的规则
<el-form ref="form1" :model="form1" :rules="rules1" label-width="100px" v-if="radio == 1"></el-form>
