583. 两个字符串的删除操作

class Solution {
public:int minDistance(string word1, string word2) {vector<vector<int>> dp(word1.size()+1, vector<int>(word2.size()+1,0));for(int i=1; i<=word1.size(); i++){for(int j=1; j<=word2.size(); j++){if(word1[i-1]==word2[j-1]) dp[i][j] = dp[i-1][j-1]+1;else dp[i][j] = max(dp[i-1][j], dp[i][j-1]);}}return word1.size()+word2.size()-2*dp[word1.size()][word2.size()];}
};

参考文章：代码随想录- 583. 两个字符串的删除操作

72. 编辑距离

class Solution {
public:int minDistance(string word1, string word2) {vector<vector<int>> dp(word1.size()+1, vector<int>(word2.size()+1, 0));for(int i=0; i<=word1.size(); i++) dp[i][0] = i;for(int j=0; j<=word2.size(); j++) dp[0][j] = j;for(int i=1; i<=word1.size(); i++){for(int j=1; j<= word2.size(); j++){if(word1[i-1]==word2[j-1]) dp[i][j] = dp[i-1][j-1];else dp[i][j] = min(dp[i][j-1]+1, min(dp[i-1][j]+1, dp[i-1][j-1]+1));}}return dp[word1.size()][word2.size()];}
};

参考文章：代码随想录-72. 编辑距离