日期问题
ac代码

#include <cstdio>
#include <iostream>using namespace std;int days[13] = {0, 31, 28, 31, 30, 31, 30, 31, 31, 30, 31, 30, 31};bool check_valid(int year, int month, int day)
{if (month == 0 || month > 12) return false;if (day == 0) return false;if (month != 2){if (day > days[month]) return false;}else{int leap = ((year % 4 == 0 && year % 100 != 0) || (year % 400 == 0));if (day > days[month] + leap) return false;}return true;
}int main()
{int a, b, c;scanf("%d/%d/%d", &a, &b, &c);for (int date = 19600101; date <= 20591231; date ++ ){int year = date / 10000, month = date % 10000 / 100, day = date % 100;if (check_valid(year, month, day)){if ((year % 100 == a && month == b && day == c) ||  // 年/月/日(month == a && day == b && year % 100 == c) ||  // 月/日/年(day == a && month == b && year % 100 == c) )   //月/日/年printf("%d-%02d-%02d\n", year, month, day);  //补前导0}}return 0;
}

本题判断完成之后需要日期从打到小排序，
1.判断是否能使用暴力，这样就避免了排序
2.如果超时，就需要将int类型日期转化为字符串存储之后排序输出