题目:
题解:
# Definition for singly-linked list.
# class ListNode:
# def __init__(self, val=0, next=None):
# self.val = val
# self.next = next
class Solution:def removeElements(self, head: ListNode, val: int) -> ListNode:dummy_head = ListNode(next=head) #添加一个虚拟节点cur = dummy_headwhile(cur.next!=None):if(cur.next.val == val):cur.next = cur.next.next #删除cur.next节点else:cur = cur.nextreturn dummy_head.next