代码实现：

在缺失的 n 个观测数据中，有 y 个观测数据是 x+1，其余观测数据都是x

int* missingRolls(int *rolls, int rollsSize, int mean, int n, int *returnSize) {int m = rollsSize;int sum = mean * (n + m);int missingSum = sum;for (int i = 0; i < m; i++) {missingSum -= rolls[i];}if (missingSum < n || missingSum > 6 * n) {*returnSize = 0;return NULL;}int x = missingSum / n, y = missingSum % n;int *res = (int*)malloc(sizeof(int) * n);for (int i = 0; i < n; i++) {res[i] = x + (i < y ? 1 : 0);}*returnSize = n;return res;
}