说明一个简单的赌博游戏,游戏规则如下:玩家掷两个骰子,点数为1到6,如果第一次点数和为7或11,则玩家胜,如果点数和为2、3或12,则玩家输,如果和 为其它点数,则记录第一次的点数和,然后继续掷骰,直至点数和等于第一次掷出的点数和,则玩家胜,如果在这之前掷出了点数和为7,则玩家输。
解法 规则看来有些复杂,但是其实只要使用switch配合if条件判断来撰写即可,小心不要弄错胜负顺序即可。
代码部分
#include <stdio.h>
#include <stdlib.h>
#include <time.h>
#define WON 0
#define LOST 1
#define CONTINUE 2int rollDice() { return (rand() % 6) + (rand() % 6) + 2;
}int main(void) {int firstRoll = 1;int gameStatus = CONTINUE;int die1, die2, sumOfDice;int firstPoint = 0;char c;srand(time(0));printf("Craps赌博游戏,按Enter键开始游戏****");while(1) {getchar();if(firstRoll) {sumOfDice = rollDice();printf("\n玩家掷出点数和:%d\n", sumOfDice);switch(sumOfDice) {case 7: case 11:gameStatus = WON; break;case 2: case 3: case 12:gameStatus = LOST; break;default:firstRoll = 0;gameStatus = CONTINUE;firstPoint = sumOfDice;break;}}else {sumOfDice = rollDice();printf("\n玩家掷出点数和:%d\n", sumOfDice);if(sumOfDice == firstPoint)gameStatus = WON;else if(sumOfDice == 7)gameStatus = LOST;}if(gameStatus == CONTINUE)puts("未分胜负,再掷一次****\n");else {if(gameStatus == WON)puts("玩家胜");elseputs("玩家输");printf("再玩一次?");scanf("%c", &c);if(c == 'n') {puts("游戏结束");break;}firstRoll = 1;}}return 0;
}