示例图
勾选一次保存后，每次进到查询都会看到被勾选的数据，代码如下：
done: function(res, curr, count) {var groupId = "[[${groupId}]]";$.ajax({url: //写后端获取数据的接口type: 'GET',success: function(data) {console.log(data);var siteIdsFromAPI = data.list.map(function(item) {return item.siteId;//这个是获取的数据对应的字段，我这里对应的是id});// 遍历表格中的每一行var $table = $('#layuitable').next().find('.layui-table tbody');var rows = $table.children('tr');rows.each(function() {var $row = $(this);var rowData = table.cache.layuitable[$row.data('index')];if (siteIdsFromAPI.includes(rowData.siteid)) {$row.find('.layui-form-checkbox').addClass('layui-form-checked');}});},error: function(xhr, status, error) {console.error("Failed to fetch siteIdFromAPI: " + error);}});// 保留原有的代码$("table").css("width", "100%");var obj = this;$("#orderList").on("click" ,function () {soulTable.render(obj);$("#order").html("<button class=\"layui-btn layui-btn-sm\" onclick='yorder()' style=\"margin-bottom: 20px\">确定</button>\n" +"<button class=\"layui-btn layui-btn-sm\" onclick='norder()' style=\"margin-bottom: 20px\">取消</button>")});}table.on('renderComplete', function() {// 遍历表格中的每一行table.checkStatus('layuitable').data.forEach(function(row) {console.log("table----",table.checkStatus('layuitable').data);var rowUserID = row.siteid;//这些是对照的idconsole.log("row.siteId",row.siteid)if (rowUserID === backendUserID) {// 获取当前行的索引var rowIndex = row.LAY_TABLE_INDEX;// 勾选当前行的复选框tableIns.setChecked('layuitable', rowIndex, true);}});});
