1、使用数组和循环实现冒泡排序

#!/bin/bash
#定义一个数组arr
arr=(4 5 2 1 3 0)
#循环比较的轮数
for ((round=0;round<${#arr[*]}-1;round++))
do#每轮比较的次数为长度-1-轮数for ((count=0;count<${#arr[*]}-1-round;count++))do#比较前一个数和后一个数的大小if [ ${arr[count]} -gt ${arr[count+1]} ];then#交换两个数temp=${arr[count]}arr[count]=${arr[count+1]}arr[count+1]=$tempfidone
echo ${arr[*]}
done

2、将冒泡排序的代码重构为2个函数，2个关系是a函数调用b函数

vim mppx2.sh

#!/bin/bash
function pk {for ((count=0; count<${#arr[*]}-1-round; count++))doif [ ${arr[count]} -gt ${arr[count+1]} ];thentemp=${arr[count]}arr[count]=${arr[count+1]}arr[count+1]=$tempfidone
}function rou {
for ((round=0; round<${#arr[*]}-1; round++))dopk doneecho ${arr[*]}
}
arr=(5 2 8 1 9)
rou "${arr[@]}"

自定义数组参数：

#!/bin/bash
function pk {for ((count=0; count<${#arr[*]}-1-round; count++))doif [ ${arr[count]} -gt ${arr[count+1]} ];thentemp=${arr[count]}arr[count]=${arr[count+1]}arr[count+1]=$tempfidone
}function rou {
for ((round=0; round<${#arr[*]}-1; round++))dopkdoneecho ${arr[*]}
}arr=($1)
rou "${arr[@]}"

3、声明一个存储的全整数数组，对其中的每一个值进行+10处理

#!/bin/bash
#定义一个数组
arr=(5 2 7 1 3)
#遍历数组中的每个数for ((count=0; count<${#arr[*]}; count++))
do
#将每个数加10
arr[count]=$(echo "${arr[count]}+10"|bc)
done
echo ${arr[*]}

4、对硬盘使用空间占比的排序

#!/bin/bash
#查看磁盘使用空间占比，并提取各个数据
mes=$( echo -n $(df -h|awk '{print $5}') )
shuzu=$(echo ${mes#*%}|tr -d '%')
arr=($shuzu)
function pk {for ((count=0; count<${#arr[*]}-1-round; count++))doif [ ${arr[count]} -gt ${arr[count+1]} ];thentemp=${arr[count]}arr[count]=${arr[count+1]}arr[count+1]=$tempfidone
}function rou {
for ((round=0; round<${#arr[*]}-1; round++))dopkdoneecho ${arr[*]}
}
rou "${arr[@]}"

5、对当前目录的文件大小进行排序

#!/bin/bash
#提取文件大小
fsz=$( echo -n $(ls -l|awk '{print $5}') )arr=("$fsz")
function pk {for ((count=0; count<${#arr[*]}-1-round; count++))doif [ ${arr[count]} -gt ${arr[count+1]} ];thentemp=${arr[count]}arr[count]=${arr[count+1]}arr[count+1]=$tempfidone
}function rou {
for ((round=0; round<${#arr[*]}-1; round++))dopk doneecho ${arr[*]}
}
rou "${arr[@]}"

或者

bash mppx2.sh "$(echo -n $(ls -l|awk '{print $5}'))"