解题思路:
int [][] arr = new int[n][m];int i = 0, j = -1, temp = 1;while (n * m > 0){for (int p = 0; p < m; p++)//从左自右arr[i][j=j+1] = temp++;n--;if (n * m == 0) break;for (int p = 0; p < n; p++)//从上自下arr[i=i+1][j] = temp++;m--;if (n * m == 0) break;for (int p = 0; p < m; p++)//从右自左arr[i][j=j-1] = temp++;n--;if (n * m == 0) break;for (int p = 0; p < n; p++)//从下自上arr[i=i-1][j] = temp++;m--;}
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【洛谷】P5731