思路很清晰，爆IV
但是题目出的有点屎，六位字符串，62的6次方，要我爆到猴年马月？
就当练习脚本吧
#Cyber2 wp
from Crypto.Cipher import DES, AES
from Crypto.Util.Padding import pad, unpad key_des = b'0a0b0c0d' # DES key must be 8 bytes long
#print(key_des)
cipher = bytes.fromhex("416935cabeb8e30cd9b56db3aa6778fa25ad5c3a5105d1c6aad4cba5f109f18afeaf5edcb8fd4e80aca82d75b42d751c40337f08df6c5231140b8c0b947362812df3dd5b5666447043240728a23da1da5cb4c7b197523b960106960cdcb6d48578667aae17caf1cb")
#print(cipher)
import string
import itertoolstable=string.ascii_letters+string.digits
#print(table)
for i in itertools.product(table,repeat = 6):x=''.join(i).encode()iv = "01" + x.decode()#print(iv)# Decryption decipher_des = DES.new(key_des, DES.MODE_CBC, (str(iv).zfill(8)).encode('utf-8')) decryptedtext_des = unpad(decipher_des.decrypt(cipher), DES.block_size) #print(decryptedtext_des)key_aes = b'0102030405060708' # AES key must be 16, 24, or 32 bytes long cipher_aes = pad(decryptedtext_des, AES.block_size)# Note: You must also store the initialization vector (IV) for decryption iv_aes = b'0807060504030201'# Decryption decipher_aes = AES.new(key_aes, AES.MODE_CBC, iv=iv_aes) decryptedtext_aes = pad(decipher_aes.decrypt(cipher_aes), AES.block_size) if (decryptedtext_aes.startswith(b"flag{")) & (decryptedtext_aes.endswith(b"}")): print(decryptedtext_aes) else: continue print("end")
)
