需求
1、长度大于8，且小于32
2、不能包含用户名
3、不能包含连续3位及以上相同字母或数字
4、不能包含3个及以上字典连续字符
4、数字、小写字母、大写字母、特殊字符，至少包含三种
package com.yy.springboottest.util;/*** @author ode* @create 2024-03-13 21:27*/
public class RegexUtil {/*** 数字*/private static final String REG_NUMBER = ".*\\d+.*";/*** 小写字母*/private static final String REG_UPPERCASE = ".*[A-Z]+.*";/*** 大写字母*/private static final String REG_LOWERCASE = ".*[a-z]+.*";/*** 特殊符号(~!@#$%^&*()_+|<>,.?/:;'[]{}\)*/private static final String REG_SYMBOL = ".*[~!@#$%^&*()_+|<>,.?/:;'\\[\\]{}\"]+.*";/*** 键盘字符表(小写)* 非shift键盘字符表*/private static final char[][] CHAR_TABLE1 = new char[][]{{'1', '2', '3', '4', '5', '6', '7', '8', '9', '0', '-', '=', '\0'},{'q', 'w', 'e', 'r', 't', 'y', 'u', 'i', 'o', 'p', '[', ']', '\\'},{'a', 's', 'd', 'f', 'g', 'h', 'j', 'k', 'l', ';', '\'', '\0', '\0'},{'z', 'x', 'c', 'v', 'b', 'n', 'm', ',', '.', '/', '\0', '\0', '\0'}};/*** shift键盘的字符表*/private static final char[][] CHAR_TABLE2 = new char[][]{{'!', '@', '#', '$', '%', '^', '&', '*', '(', ')', '_', '+', '\0'},{'q', 'w', 'e', 'r', 't', 'y', 'u', 'i', 'o', 'p', '{', '}', '|'},{'a', 's', 'd', 'f', 'g', 'h', 'j', 'k', 'l', ':', '"', '\0', '\0'},{'z', 'x', 'c', 'v', 'b', 'n', 'm', '<', '>', '?', '\0', '\0', '\0'}};public static void main(String[] args) {String password = "qaz124edYY";System.out.println(checkPasswordRule(password, " "));}/*** 校验密码** @param password 密码* @param username 用户名*/public static boolean checkPasswordRule(String password, String username) {if (password == null || password.length() < 8 || password.length() > 32) {System.out.println("长度小于8，或大于32");return false;}if (password.contains(username)) {System.out.println("包含用户名");return false;}if (isContinuousChar(password)) {System.out.println("包含3个及以上相同或字典连续字符");return false;}if (isKeyBoardContinuousChar(password)) {System.out.println("包含3个及以上键盘连续字符");return false;}int i = 0;if (password.matches(REG_NUMBER)) i++;if (password.matches(REG_LOWERCASE)) i++;if (password.matches(REG_UPPERCASE)) i++;if (password.matches(REG_SYMBOL)) i++;if (i < 3) {System.out.println("数字、小写字母、大写字母、特殊字符，至少包含三种");return false;}return true;}/*** 是否包含3个及以上相同或字典连续字符*/private static boolean isContinuousChar(String password) {char[] chars = password.toCharArray();for (int i = 0; i < chars.length - 2; i++) {int n1 = chars[i];int n2 = chars[i + 1];int n3 = chars[i + 2];// 判断重复字符if (n1 == n2 && n1 == n3) {return true;}// 判断连续字符： 正序 + 倒序if ((n1 + 1 == n2 && n1 + 2 == n3) || (n1 - 1 == n2 && n1 - 2 == n3)) {return true;}}return false;}/*** 是否包含3个及以上键盘连续字符** @param password 待匹配的字符串*/private static boolean isKeyBoardContinuousChar(String password) {if (password == null) {return false;}//考虑大小写，都转换成小写字母char[] lpStrChars = password.toLowerCase().toCharArray();// 获取字符串长度int nStrLen = lpStrChars.length;// 定义位置数组：row - 行，col - column 列int[] pRowCharPos = new int[nStrLen];int[] pColCharPos = new int[nStrLen];for (int i = 0; i < nStrLen; i++) {char chLower = lpStrChars[i];pColCharPos[i] = -1;// 检索在表1中的位置，构建位置数组for (int nRowTable1Idx = 0; nRowTable1Idx < 4; nRowTable1Idx++) {for (int nColTable1Idx = 0; nColTable1Idx < 13; nColTable1Idx++) {if (chLower == CHAR_TABLE1[nRowTable1Idx][nColTable1Idx]) {pRowCharPos[i] = nRowTable1Idx;pColCharPos[i] = nColTable1Idx;}}}// 在表1中没找到，到表二中去找，找到则continueif (pColCharPos[i] >= 0) {continue;}// 检索在表2中的位置，构建位置数组for (int nRowTable2Idx = 0; nRowTable2Idx < 4; nRowTable2Idx++) {for (int nColTable2Idx = 0; nColTable2Idx < 13; nColTable2Idx++) {if (chLower == CHAR_TABLE2[nRowTable2Idx][nColTable2Idx]) {pRowCharPos[i] = nRowTable2Idx;pColCharPos[i] = nColTable2Idx;}}}}// 匹配坐标连线for (int j = 1; j <= nStrLen - 2; j++) {//同一行if (pRowCharPos[j - 1] == pRowCharPos[j] && pRowCharPos[j] == pRowCharPos[j + 1]) {// 键盘行正向连续（asd）或者键盘行反向连续（dsa）if ((pColCharPos[j - 1] + 1 == pColCharPos[j] && pColCharPos[j] + 1 == pColCharPos[j + 1]) ||(pColCharPos[j + 1] + 1 == pColCharPos[j] && pColCharPos[j] + 1 == pColCharPos[j - 1])) {return true;}}//同一列if (pColCharPos[j - 1] == pColCharPos[j] && pColCharPos[j] == pColCharPos[j + 1]) {//键盘列连续（qaz）或者键盘列反向连续（zaq）if ((pRowCharPos[j - 1] + 1 == pRowCharPos[j] && pRowCharPos[j] + 1 == pRowCharPos[j + 1]) ||(pRowCharPos[j - 1] - 1 == pRowCharPos[j] && pRowCharPos[j] - 1 == pRowCharPos[j + 1])) {return true;}}}return false;}}
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