思路 ： 遍历计算每个元素比它大的元素个数，并判断做出对应结果标签；

#include <iostream>
#include <vector>using namespace std;class Solution {
public:vector<string> findRelativeRanks(vector<int>& score) {int counter = 0;vector<string> res;for (auto i : score){for (auto j : score){if (i < j) counter++;}if (counter == 0) res.push_back("Gold Medal");else if (counter == 1) res.push_back("Silver Medal");else if (counter == 2) res.push_back("Bronze Medal");else res.push_back(to_string(counter + 1));counter = 0;}return res;}
};int main() {Solution s;vector<int> score = {5,4,3,2,1};vector<string> res = s.findRelativeRanks(score);for (auto i : res) cout << i << " ";cout << endl;return 0;
}