目录

1.题目描述 

描述

输入描述：

输出描述：

示例1

2.解题  

---

 

1.题目描述 

描述

KiKi想获得某年某月有多少天，请帮他编程实现。输入年份和月份，计算这一年这个月有多少天。

输入描述：

多组输入，一行有两个整数，分别表示年份和月份，用空格分隔。

输出描述：

针对每组输入，输出为一行，一个整数，表示这一年这个月有多少天。

示例1

输入：

2008 2

复制输出：

29

2.解题  

int main(){int year = 0;int mouth = 0;while ((scanf("%d %d", &year, &mouth)) != EOF){if (((year % 100 != 0) && (year % 4 == 0)) || (year % 400 == 0)){if (mouth == 2){printf("29\n");}else if (mouth == 1 || mouth == 3 || mouth == 5 || mouth == 7 || mouth == 8 || mouth == 10 || mouth == 12){printf("31\n");}else{printf("30\n");}}else{if (mouth == 2){printf("28\n");}else if (mouth == 1 || mouth == 3 || mouth == 5 || mouth == 7 || mouth == 8 || mouth == 10 || mouth == 12){printf("31\n");}else{printf("30\n");}}}return 0;}

第二种解法：

#include <stdio.h>
int main()
{int y = 0;int m = 0;int days[12] = {31,28,31,30,31,30,31,31,30,31,30,31}; while(scanf("%d%d", &y, &m) != EOF){int day = days[m-1];if((y%4==0 && y%100!=0) || (y%400==0)){if(m == 2)day += 1;}printf("%d\n", day);}return 0;
}