题目链接:
自己的做法:
#include <bits/stdc++.h>using namespace std;const int N = 1e5 + 10;
int a[N], b[N];
int main()
{int n, m;bool flag = true;scanf("%d%d", &n, &m);for (int i = 0; i < n; i++) scanf("%d", &a[i]);for (int i = 0; i < m; i++) scanf("%d", &b[i]);int j = 0, i = 0;while (j < m && i < n) {if (a[i] == b[j]) i++, j++, flag = true;else j++, flag = false;}if (i == n && flag) cout << "Yes";else cout << "No";return 0;
}
推荐解法: