long类型20位示例
长类numberOfTrailingZeros()方法 (Long class numberOfTrailingZeros() method)
numberOfTrailingZeros() method is available in java.lang package.
在java.lang包中提供了numberOfTrailingZeros()方法 。
numberOfTrailingZeros() method is used to returns the number of 0's bits following the rightmost one bit in the 2's complement denotation of the given parameter [value] of long type.
numberOfTrailingZeros()方法用于返回long类型给定参数[value]的2的补码表示法中最右边一位之后的0位数。
numberOfTrailingZeros() method is a static method, it is accessible with the class name too and if we try to access the method with the class object then also we will not get an error.
numberOfTrailingZeros()方法是一个静态方法,也可以使用类名进行访问,如果我们尝试使用类对象访问该方法,那么也不会出错。
numberOfTrailingZeros() method does not throw an exception at the time of trailing zeros.
在尾随零时, numberOfTrailingZeros()方法不会引发异常。
Syntax:
句法:
public static int numberOfTrailingZeros (long value);
Parameter(s):
参数:
long value – represents the long value to be parsed.
long value –表示要解析的long值。
Return value:
返回值:
The return type of this method is int, it returns the integer value based on the following cases,
此方法的返回类型为int ,它基于以下情况返回整数值:
If the given argument is non-zero then, it returns the number of 0's bits followed the rightmost bit one bit in 2's complement of the given long value.
如果给定的参数不为零,则返回给定long值的2的补码中,最右边的一位之后是0的位数。
Else, if the given argument is zero then, it returns the value 64 because it has no 1's bits in 2's complement of the given argument.
否则,如果给定参数为零,则它将返回值64,因为在给定参数的2的补码中没有1的位。
Example:
例:
// Java program to demonstrate the example
// of numberOfTrailingZeros (long value) method of Long class
public class NumberOfTrailingZerosOfLongClass {
public static void main(String[] args) {
long value1 = 1296;
long value2 = 0;
// It returns the string representation of the given unsigned
// long value denoted by the argument in binary by calling
// Long.toBinaryString(value1)
System.out.println("Long.toBinaryString(value1): " + Long.toBinaryString(value1));
// It returns the string representation of the given unsigned
// long value denoted by the argument in binary by calling
// Long.toBinaryString(value2)
System.out.println("Long.toBinaryString(value2):" + Long.toBinaryString(value2));
// It returns the number of 0's bits following the leftmost side
// one bit in the given argument 'value' by calling
// Long.numberOfTrailingZeros(value1)
System.out.println("Long.numberOfTrailingZeros(value1): " + Long.numberOfTrailingZeros(value1));
// It returns the value 64 because the value of the given argument is zero
System.out.println("Long.numberOfTrailingZeros(value2): " + Long.numberOfTrailingZeros(value2));
}
}
Output
输出量
Long.toBinaryString(value1): 10100010000
Long.toBinaryString(value2):0
Long.numberOfTrailingZeros(value1): 4
Long.numberOfTrailingZeros(value2): 64
翻译自: https://www.includehelp.com/java/long-class-numberoftrailingzeros-method-with-example.aspx
long类型20位示例