我在backend / views / site下添加了help.php,并在SiteController.php下声明了一个能够识别链接的函数

public function behaviors()

{

return [

'access' => [

'class' => AccessControl::className(),

'rules' => [

[

'actions' => ['login', 'error'],

'allow' => true,

],

[

'actions' => ['logout', 'index'],

'allow' => true,

'roles' => ['@'],

],

],

],

'verbs' => [

'class' => VerbFilter::className(),

'actions' => [

'logout' => ['post'],

],

],

];

}

public function actionHelp()

{

return $this->render('help');

}

该链接现在可以访问,但它给了我一个错误

禁止(#403)并且它说“你不被允许执行这个动作.”

现在,我想问一下我是如何查看我创建的网页的.提前致谢.

解决方法:

该问题与AccessControl过滤器有关.

您可以将帮助操作添加到此允许操作列表中,例如：

[

'actions' => ['login', 'error', 'help'],

'allow' => true,

],

您可以内容并根据documentation section检查访问规则的应用方式.

标签：php,yii2

来源： https://codeday.me/bug/20190702/1361122.html