九宫格键盘输入
Letter Combinations of a Phone Number
给定一个数字字符串,返回数字可能代表的所有可能的字母组合。
数字到字母的映射(就像九宫格电话按钮一样)如下图。
Given a digit string, return all possible letter combinations that the number could represent.
A mapping of digit to letters (just like on the telephone buttons) is given below.
Note:
Although the above answer is in lexicographical order, your answer could be in any order you want.
example 1
Input:Digit string "23"
Output: ["ad", "ae", "af", "bd", "be", "bf", "cd", "ce", "cf"].
思路
以23为例,2代表abc,只需要将其转换成lists = [a,b,c],然后处理3,3为def,将这三个字符分别加到s的每一个元素中,得到["ad", "ae", "af", "bd", "be", "bf", "cd", "ce", "cf"]。重复此过程即可。
上述思路可以用循环完成,同时python提供的reduce函数和生成式特性能够精炼地表述,下面给出两种代码。
代码
class Solution(object):
def letterCombinations(self, digits):
"""
:type digits: str
:rtype: List[str]
"""
from functools import reduce #python3.x
if not digits:
return []
nums = '0 1 abc def ghi jkl mno pqrs tuv wxyz'.split(' ')
return reduce(lambda last, d: [x + y for x in last for y in nums[int(d)]], digits, ['']) # 第三个参数是initial
#使用循环完成
def letterCombinations_old(self, digits):
if not digits:
return []
nums = '0 1 abc def ghi jkl mno pqrs tuv wxyz'.split(' ')
ret = [_ for _ in nums[int(digits[0])]]
digits = digits[1:]
while digits:
ret = [x + y for x in ret for y in nums[int(digits[0])]]
digits = digits[1:]
return ret
本题以及其它leetcode题目代码github地址: github地址
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