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的确很奇怪。我试验了10几分钟，你按下面的方法来做就可以正确。import struct

zzz = ("{Type:2}").encode("utf-8")

length = len(zzz)

a = struct.pack("%ds"%length,zzz)

print(a)

简单的说32313133353236313431303231363533e59b9ee7ad9431333335326138s其实只是一个字符，所以前面要加一个数字，比如8s，就可以存贮一个长度为8的字符串。你只写一个s当然只存贮一个。

python帮助的原文如下

For the 's' format

character, the count is interpreted as the size of the string, not a repeat

count like for the other format characters; for example, '10s' means a single

10-byte string, while '10c' means 10 characters. If a count is not given, it

defaults to 1. For packing, the string is truncated or padded with null bytes as

appropriate to make it fit. For unpacking, the resulting string always has

exactly the specified number of bytes. As a special case, '0s' means a single, empty

string (while '0c'

means 0 characters).