如果可以的话，我会建议改变你正在jQuery的请求发送到以下方式：

var h1 = []

h2 = []

h3 = [],

layout = $("input[type=radio][name='layout_option']:checked").val();

$("ul.widget-order[name='1'] li").each(function() { h1.push($(this).attr('id')); });

$("ul.widget-order[name='2'] li").each(function() { h2.push($(this).attr('id')); });

$("ul.widget-order[name='3'] li").each(function() { h3.push($(this).attr('id')); });

var sendData = JSON.stringify({

ids1: " " + h1 + "",

ids2: " " + h2 + "",

ids3: " " + h3 + ""

});

var sPayload = "data=" + encodeURIComponent(sendData) + "&layout=" + encodeURIComponent(layout);

$.ajax({

type: "POST",

url: "_backend/account/updateWidgets.php",

data: sPayload,

success: function(data){

$("#post_reply").html(data);

console.log({ data: sendData });

}

});

有在您发布的代码中发现了一些语法错误，这些错误在我的答案中包含的代码中已得到纠正，但最重要的是，我已将您的数据修改为全部编码。看起来你正在试图将JSON对象与编码为application/x-www-form-urlencoded的标准数据结合起来。我已经在上面的代码中对此进行了标准化，因此所有数据均发布为application/x-www-form-urlencoded。

在你的PHP，你就可以访问此为：

// First, let's get the layout because that's the easiest

$layout = (isset($_POST['layout']) ? $_POST['layout'] : NULL);

// As a note, the isset(...) with ternary operator is just my preferred method for checking missing data when extracting that data from the PHP super-globals.

// Now we'll need to get the JSON portion.

$jData = $_POST['data'];

$data = json_decode($jData, $assoc=true);

echo "ids1 is " . $data['ids1'] . "\n
\n";

echo "ids2 is " . $data['ids2'] . "\n
\n";

echo "ids3 is " . $data['ids3'] . "\n
\n";

?>