1.2 - 列表练习题

1.创建列表
>>> names = ['old_driver', 'rain', 'jack', 'shanshan', 'peiqi', 'black_girl']
>>> names
['old_driver', 'rain', 'jack', 'shanshan', 'peiqi', 'black_girl'] 

2.插入alex
>>> names.insert(-1,'alex')
>>> names
['old_driver', 'rain', 'jack', 'shanshan', 'peiqi', 'alex', 'black_girl']

3.shanshan改成中文
>>> names
['old_driver', 'rain', 'jack', 'shanshan', 'peiqi', 'alex', 'black_girl']
>>> names.index('shanshan')
3
>>> names[names.index('shanshan')] = "珊珊"
>>> names
['old_driver', 'rain', 'jack', '珊珊', 'peiqi', 'alex', 'black_girl']

4.rain后面插一个子列表 
>>> names.insert(2,['oldboy','oldgirl'])
>>> names
['old_driver', 'rain', ['oldboy', 'oldgirl'], 'jack', '珊珊', 'peiqi', 'alex', 'black_girl']

5.得到peiqi得索引值
>>> names.index('peiqi')
5

6.创建新列表并合入names列表中
>>> s = [1,2,3,4,2,5,6,2]
>>> s
[1, 2, 3, 4, 2, 5, 6, 2]
>>> names.extend(s)
>>> names
['old_driver', 'rain', ['oldboy', 'oldgirl'], 'jack', '珊珊', 'peiqi', 'alex', 'black_girl', 1, 2, 3, 4, 2, 5, 6, 2]

7.取出names列表4-7得元素
>>> names
['old_driver', 'rain', ['oldboy', 'oldgirl'], 'jack', '珊珊', 'peiqi', 'alex', 'black_girl', 1, 2, 3, 4, 2, 5, 6, 2]
>>> names[4:7]
['珊珊', 'peiqi', 'alex']

8.取出name列表2-10得元素步长为2
>>> names[2:10:2]
[['oldboy', 'oldgirl'], '珊珊', 'alex', 1]

9.取出列表最后3个元素
>>> names[-3:]
[5, 6, 2]

10.循环列表 打印每个元素得索引值和元素
>>> for i in names:
    print(names.index(i),  i)

    
0 old_driver
1 rain
2 ['oldboy', 'oldgirl']
3 jack
4 珊珊
5 peiqi
6 alex
7 black_girl
8 1
9 2
10 3
11 4
9 2
13 5
14 6
9 2
>>> 

>>> count = 0
>>> for i in names:
    print(count,i)
    count += 1

    
0 old_driver
1 rain
2 ['oldboy', 'oldgirl']
3 jack
4 珊珊
5 peiqi
6 alex
7 black_girl
8 1
9 2
10 3
11 4
12 2
13 5
14 6
15 2
>>> 

>>> for i in enumerate(names):
    print(i)

    
(0, 'old_driver')
(1, 'rain')
(2, ['oldboy', 'oldgirl'])
(3, 'jack')
(4, '珊珊')
(5, 'peiqi')
(6, 'alex')
(7, 'black_girl')
(8, 1)
(9, 2)
(10, 3)
(11, 4)
(12, 2)
(13, 5)
(14, 6)
(15, 2)
>>> 

>>> for index,i in enumerate(names):
    print(index,i)

    
0 old_driver
1 rain
2 ['oldboy', 'oldgirl']
3 jack
4 珊珊
5 peiqi
6 alex
7 black_girl
8 1
9 2
10 3
11 4
12 2
13 5
14 6
15 2
>>> 

11.循环列表 打印索引值和元素 索引值为偶数时 对应得元素改成1
for index,i in enumerate(names):
    if index % 2 == 0:
        names[index] = 0
print(names)

12.names有3个2 返回第二个2得索引值 
names = [-1, 'rain', -1, 'jack', -1, 'peiqi', -1, 'black_girl', -1, 2, -1, 4, -1, 5, -1, 2, 2]
first_index = names.index(2)
new_list = names[first_index+1:]
second_index = new_list.index(2)
second_val = names[first_index+second_index+1]
print(new_list,first_index,second_index)
print("second_val:",second_val)

13.打印商品列表
products = [['Iphone8',6888],['MacPro',14800],['小米6',2499],['Coffee',31],['Book',80],['Nike Shoes',799]]
print("-------商品列表------")
for index, i in enumerate(products):
    print("%s. %s    %s" % (index, i[0], i[1]))


14.
# 14 商品 不断问用户想买什么 用户选择一个商品编号 放在购物车里 最终用户输入q退出 打印 购物车商品列表 
products = [['Iphone8',6888],['MacPro',14800],['小米6',2499],['Coffee',31],['Book',80],['Nike Shoes',799]]
shopping_cart = []

# run_flag = True
exit_flag = False

while not exit_flag:
    print("-------商品列表------")
    for index, i in enumerate(products):
        print("%s. %s    %s" % (index, i[0], i[1]))

    choice = input("输入想买得商品编号：")
    if choice.isdigit():
        choice = int(choice)
        if choice >= 0  and choice < len(products):
            shopping_cart.append(products[choice])
            print("Added products %s into shoppong_cart" % (products[choice]))
        else:
            print("商品不存在")
    elif choice == 'q':
        if len(shopping_cart) > 0:
            print("------------你已购买以下商品----------")
            for index,i in enumerate(shopping_cart):
                print("%s. %s    %s" % (index, i[0], i[1]))
       # break
       # run_flag = False
        exit_flag = True