my_atio()代码出错原因，完全代码

1、

//不明白这么简单的代码为什么会出错

#include

int my_atoi(char *str);

int main(void)

{

char a[]=" 12345";

int b=0;

b = my_atoi(a);

printf("%d", b);

getchar();

return 0;

}

int my_atoi(char *str)

{

char* p = str;//char *p; p = str;

int inter_symbol = 1;

int inter_number = 0;

while (*p = ' ')//出错的地方

p++;

if (*p = '-')

{

inter_symbol = inter_symbol*(-1);

p++;

}

while(*p>='0'&&*p<='9'&&*p!='\n')

{

inter_number = inter_number * 10 + (*p - '0');

p++;

}

return inter_number*inter_symbol;

}

调试了好久，才知道原来判断语句的“==”写成了“=”！！！切实记得这个错误！！

2、

#include
int my_atoi(char *str)
{
char *p = str;//char *p; p = str;
int inter_symbol = 1;
int inter_number = 0;
while (*p == ' ')
  p++;
if (*p == '-')
{
  inter_symbol =inter_symbol*(-1);
  p++;
}
if (*p == '+')
{
  p++;
}
if (!(*p >= '0'&&*p <= '9'))
{
  printf("开始符号为非数字字符，错误返回。\n");
  return 0;
}
while (*p != '\0')
{
  if (*p >= '0'&&*p<= '9')
  {
   inter_number= inter_number * 10 + (*p - '0');
   p++;
  }
  else
  {
   printf("字符串不完全是数字字符，返回部分数字字符对应的数字\n");
   returninter_number*inter_symbol;
  }
}
return inter_number*inter_symbol;
}

int main(void)
{
char a[] = "1a2355";
char b[] = "987653";
int add1,add2,total;
add1 = my_atoi(a);
add2 = my_atoi(b);
total = add1 + add2;
printf("%d", total);
getchar();
return 0;
}