题目网址

题目解析

1.输入一串数字,如果有1就输出HARD,否则输出EASY
2.勿忘&

代码

#include<stdio.h>
#include<stdlib.h>
#include<string.h>
int main()
{int n=0,i=0;int num=0;int count=0;scanf("%d",&n);for(i;i<n;i++){scanf("%d",&num);if(num==1){count=1;break;}}if(count){printf("HARD");}else{printf("EASY");}system("pause");getchar();return 0;
}