源码
\begin{array}{lr}
& x+1 \\
x+1 \!\!\!\!\!\! & \overline{)x^2 + 2x + 1} \\
& \underline{x^2+\ \ x\ \ \ \ \ \ \ } \\
& x + 1 \\
& \underline{x+1} \\
& 0
\end{array}
效果
x+1x+1 )x2+2x+1‾x2+x‾x+1x+1‾0\begin{array}{lr} & x+1 \\ x+1 \!\!\!\!\!\! & \overline{)x^2 + 2x + 1} \\ & \underline{x^2+\ \ x\ \ \ \ \ \ \ } \\ & x + 1 \\ & \underline{x+1} \\ & 0 \end{array} x+1x+1)x2+2x+1x2+ x x+1x+10
