hdu 4322 最大费用流

题目链接：http://acm.hdu.edu.cn/showproblem.php?pid=4322

#include <cstdio>
#include <cstring>
#include <iostream>
#include <cmath>
#include <algorithm>
#include <queue>
#include <vector>
using namespace std;const int maxe = 50000;
const int maxn = 30;
const int INF  = 0x3f3f3f;struct Edge{int u,v,flow,cap,cost;int next;Edge(int u=0,int v=0,int flow=0,int cap=0,int cost=0,int next=0):u(u), v(v),  flow(flow), cap(cap),  cost(cost), next(next) {}
};struct MCMF{int d[maxn];bool inq[maxn];Edge edges[maxe];int head[maxn],cnt;int pa[maxn];   //用于回溯找增广路。int res[maxn];void init(){memset(head,-1,sizeof(head));cnt = 0;}void addedge(int u,int v,int cap,int cost){edges[cnt] = Edge(u,v,0,cap,cost,head[u]);head[u] = cnt++;edges[cnt] = Edge(v,u,0,0,-cost,head[v]);head[v] = cnt++;}bool SPFA(int s,int t,int& flow,int& cost){memset(inq,0,sizeof(inq));memset(d,-0x3f,sizeof(d));     //这个才是WA无数次的原因，看别人的代码才知道。queue<int> Q;Q.push(s);d[s] = 0;        inq[s] = true;res[s] = INF;    res[t] = 0;while(!Q.empty()){int u = Q.front();  Q.pop();inq[u] = false;for(int i=head[u];i!=-1;i=edges[i].next){Edge& e = edges[i];if(e.cap > e.flow && d[e.v] < d[u] + e.cost){d[e.v] = d[u] + e.cost;pa[e.v] = i;res[e.v] = min(res[u],e.cap-e.flow);if(!inq[e.v]){Q.push(e.v);   inq[e.v] = true;}}}}if(res[t] == 0)  return false;flow += res[t];cost += res[t]*d[t];for(int i=t;i!=s;i=edges[pa[i]].u){edges[pa[i]].flow   += res[t];edges[pa[i]^1].flow -= res[t];}return true;}bool MaxCost(int s,int t,int N,int sumB){int flow = 0,cost = 0;while(SPFA(s,t,flow,cost)) {}return N - flow >= sumB - cost;}
}solver;int main()
{//freopen("E:\\acm\\input.txt","r",stdin);int T;cin>>T;for(int cas=1;cas<=T;cas++){solver.init();int N,M,K;cin>>N>>M>>K;int B[maxn];int sumB = 0;for(int i=1;i<=M;i++)  { cin>>B[i];  sumB += B[i]; }int s = 0, t = N+M+1;for(int i=1;i<=N;i++)  solver.addedge(s,i,1,0);int like[maxn][maxn];for(int i=1; i<=M; i++)for(int j=1; j<=N; j++){scanf("%d",&like[i][j]);if(like[i][j])solver.addedge(j,i+N,1,0);}/**for(int i=1;i<=M;i++)for(int j=1;j<=N;j++){int flag;scanf("%d",&flag);if(flag)  solver.addedge(j,i+N,1,0);}这个代码与上面的那段功能相同，但我不知道为啥会错。我怀疑是oj的问题。
**/for(int i=1;i<=M;i++){solver.addedge(N+i,t,B[i]/K,K);if(B[i]%K > 1)solver.addedge(N+i,t,1,B[i]%K);}if(solver.MaxCost(s,t,N,sumB))  printf("Case #%d: YES\n",cas);else                            printf("Case #%d: NO\n",cas);}
}