我实际上检查了我的代码一百次,但我找不到错误：

我得到的错误：

解析错误：语法错误,意外$end在/home/tennox/public_html/php/kalender.php第46行

我试图做一个计算复活节星期日的函数,在另一个脚本中没有其他所有它只是起作用,但在这个没有.另一种方式围绕同样的事情！

$year = isset($_POST['year']) ? intval($_POST['year']) : date('Y');

$months = array("", "Januar", "Februar", "März", "April", "Mai", "Juni", "Juli", "August", "September", "Oktober", "November", "Dezember");

$days = array('So', 'Mo', 'Di', 'Mi', 'Do', 'Fr', 'Sa');

$ostern = getOsterSonntag($year);

?>

for($y=0; $y<32; $y++) {

echo "

";

for($x=1; $x<=12; $x++) {

echo "

";

$date = strtotime("$y.$x.$year");

$day = date("d", $date);

$dayname = $days[date("w", $date)];

if ($y == 0) {

echo "

";

} elseif ($y < date("t",$date) && !($y == 30 && $x == 2)) {

if (date("w", $date) == 6 || date("w", $date) == 0)

echo "";

echo "$day $dayname";

if ($date == $ostern)

echo "(Ostersonntag)";

if (date("w", $date) == 6 || date("w", $date) == 0)

echo "";

} else {

echo " - ";

}

echo "

";

}

echo "

";

}

?>

function getOsterSonntag($year) {

$a = $year % 19;

$b = $year % 4;

$c = $year % 7;

$k = floor($year / 100);

$p = floor((8*$k + 13) / 25);

$q = ($k / 4);

$d = (19*$a + ((15 + $k - $p - $q) % 30)) % 30;

$e = (2*$b + 4*$c + 6*$d + ((4 + $k - $q) % 7)) % 7;

$ostern = 22 + $d + $e;

if ($ostern > 31){

$ostern -= 31;

return strtotime("$ostern.4.$year");

} else

return strtotime("$ostern.3.$year");

}

?>