C. Simple Strings：题目

思路：简单的离谱，就相同就换就行，哪有dp的事啊

#include <bits/stdc++.h>
using namespace std;
typedef long long ll;
vector<ll> a((int)6e5);
vector<ll> b((int)6e5);
string str;
int main()
{cin>>str;int len = str.length();for (int i=1;i<len;i++){if (str[i]==str[i-1]){if (str[i-1]=='z') str[i] = 'a';else str[i] = str[i-1]+1;if (i<len-1&&str[i]==str[i+1]){if (str[i+1]=='z') str[i] = 'a';else str[i]++;}}}cout<<str<<endl;
}