例如现在有这样一个Json

String Value =  {"data":[{"school_name":"西北农林科技大学","school_id":"8"},{"school_name":"西北大学","school_id":"6"},{"school_name":"西北工业大学","school_id":"5"},{"school_name":"西北政法大学","school_id":"2"},{"school_name":"西安交通大学","school_id":"4"},{"school_name":"西安建筑科技大学","school_id":"10"},{"school_name":"西安电子科技大学","school_id":"3"},{"school_name":"西安邮电大学","school_id":"1"},{"school_name":"长安大学","school_id":"9"},{"school_name":"陕西师范大学","school_id":"7"},{"school_name":"陕西科技大学","school_id":"11"}],"msg":"列表获取成功","status":0}

用2个数组接收school_name和school_id

首先

public   String[] schoolID;

public  String[] schoolName;

JSONObject  jsonObj_school；//用来接收解析的JSON字符串

JSONArray  jsonArr_school ；//用来接收JSON对象里的数组

try{

jsonObj_school = new JSONObject ( Value); //解析JSON字符串

jsonArr_school  =jsonObj_school.getJSONArray("data");//接收JSON对象里的数组

int jsonSize_school = jsonArr_school.length();.//获取数组长度

schoolID = new String[ jsonSize_school ];//初始化数组

schoolName = new String[ jsonSize_school];//初始化数组

for(int i = 0; i < jsonSize_school; i++ )//通过循环取出数组里的值

{

JSONObject jsonTemp = (JSONObject)jsonArr_school.getJSONObject(i);

schoolID[i] = jsonTemp.getString("school_id");

schoolName[i] = jsonTemp.getString("school_name");

}

}

catch(Exception e){

e.printStackTrace();

}