我正在尝试在Python 3.3中创建一个简单的程序,该程序采用四个名称的列表,并将它们随机分配给列表中的另一个人.例如,如果名称是John,Aaron,Lydia和Robin：

约翰先走,然后选择一个名字.他不能画自己的东西.如果他这样做,他会把它放回去并再次抽签.说约翰画了罗宾的名字.罗宾的名字将从游泳池中淘汰.接下来是亚伦的抽奖.他画约翰.约翰的名字被淘汰了.等等,直到分配了所有名称.

我创建了一个具有四个名称的列表,并为每个名称分配了一个值1-4.但是,从列表中删除时我遇到了一个问题,说该值不存在.

list.remove(x)：x不在列表中.

它看起来像这样：

def drawNames():

import random

John=1

Aaron=2

Lydia=3

Robin=4

validNames=[John, Aaron, Lydia, Robin]

nameDrawn=random.choice(validNames)

def draw():

nameDrawn=random.choice(validNames)

#John's Draw:

draw()

if nameDrawn != 1:

if nameDrawn == 2:

print("John drew: Aaron")

validNames.remove(2)

elif nameDrawn == 3:

print("John drew: Lydia")

validNames.remove(3)

elif nameDrawn == 4:

print("John drew: Robin")

validNames.remove(4)

#Aaron's Draw:

draw()

if nameDrawn !=2:

if nameDrawn ==1:

print("Aaron drew: John")

validNames.remove(1)

elif nameDrawn ==3:

print("Aaron drew: Lydia")

validNames.remove(3)

elif nameDrawn ==4:

print("Aaron drew: Robin")

validNames.remove(4)

#Lydia's Draw:

draw()

if nameDrawn !=3:

if nameDrawn ==1:

print("Lydia drew: John")

validNames.remove(1)

elif nameDrawn ==2:

print("Lydia drew: Aaron")

validNames.remove(2)

elif nameDrawn ==4:

print("Lydia drew: Robin")

validNames.remove(4)

#Robin's Draw:

draw()

if nameDrawn !=4:

if nameDrawn ==1:

print("Robin drew: John")

validNames.remove(1)

elif nameDrawn ==2:

print("Robin drew: Aaron")

validNames.remove(2)

elif nameDrawn ==3:

print("Robin drew: Lydia")

validNames.remove(3)

drawNames()

我也尝试过使用名称而不是数字值,这会产生相同的错误.

我也觉得这是一个低效的方案.如果您有更好的建议,我将非常有义务.

解决方法:

使用下面的代码,可能会获得更好的里程；与上面提供的名称相比,它可以扩展到许多名称.

import copy

import random

validNames=["John", "Aaron", "Lydia", "Robin"]

def drawNames(namelist,currentname):

'''

namelist: list of names to draw from

currentname: name of person doing the current draw

'''

draw_namelist = copy.copy(namelist) # make a copy to remove person drawing if needed

if currentname in draw_namelist: # check if the person drawing is in the list

draw_namelist.remove(currentname) # remove current name if in list

try:

drawn_name = random.choice(draw_namelist)

namelist.remove(drawn_name)

newnamelist = namelist

print "Drew {}".format(drawn_name)

print "New list: {}".format(newnamelist)

except:

print "Nobody for me to draw!"

drawn_name=None

newnamelist = namelist

return drawn_name, newnamelist

然后可以按以下方式工作：

In [39]: newlist=["John", "Aaron", "Lydia", "Robin"]

In [40]: name,newlist = drawNames(newlist,"Lydia")

Drew Robin

New list: ['John', 'Aaron', 'Lydia']

In [41]: name,newlist = drawNames(newlist,"John")

Drew Aaron

New list: ['John', 'Lydia']

In [42]: name,newlist = drawNames(newlist,"Aaron")

Drew John

New list: ['Lydia']

In [43]: name,newlist = drawNames(newlist,"Robin")

Drew Lydia

New list: []

标签：python-3-x,list,scripting,python

来源： https://codeday.me/bug/20191122/2059453.html