1 #coding:utf-8

2 list1 = ['physics', 'chemistry', 1997, 2000];

3 list2 = [1, 2, 3, 4, 5 ];

4 list3 = ["a", "b", "c", "d"];

5

6 #切片功能跟str一样

7 print "list1[0]: ", list1[0]

8 print "list2[1:5]: ", list2[1:5]

9 print list1[::-1]

10 list3.append("e")# 追加

11 print list3

12

13 del list1[2];

14 print list1;

15

16 list4 = list2 + list3

17

18 print list4

19

20 print 3 in list2

21

22 for item in list2:

23 print item

24

25 #等价

26 # for i in range(len(list2)):

27 # print list2[i]

28

29 # list_2d = [[0 for col in range(cols)] for row in range(rows)]

30 list_2d = [ [0 for i in range(5)] for i in range(4)] #2维数据, 0为初始化数值

31

32 print list_2d

33 list_2d[0][1]=1

34 print list_2d

输出----------------------------------------------------

list1[0]: physics

list2[1:5]: [2, 3, 4, 5]

[2000, 1997, 'chemistry', 'physics']

['a', 'b', 'c', 'd', 'e']

['physics', 'chemistry', 2000]

[1, 2, 3, 4, 5, 'a', 'b', 'c', 'd', 'e']

True

1

2

3

4

5

[[0, 0, 0, 0, 0], [0, 0, 0, 0, 0], [0, 0, 0, 0, 0], [0, 0, 0, 0, 0]]

[[0, 1, 0, 0, 0], [0, 0, 0, 0, 0], [0, 0, 0, 0, 0], [0, 0, 0, 0, 0]]

标签：python,list1,list,list2,2d,range,print,操作

来源： https://www.cnblogs.com/xiebinbo/p/10997075.html