正题

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大意

就是将1到10改为
“unu”,”du”,”tri”,”kvar”,”kvin”,”ses”,”sep”,”ok”,”nau”,”dek”

然后如果是十几：
如12：”dek du”

如果是几十几：
如88：”dudek du”

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解题思路

就是判断就好了，比打表还快

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代码

#include<cstdio>
using namespace std;
int x;
char s[10][5]={"dek","unu","du","tri","kvar","kvin","ses","sep","ok","nau"};
//数字表
int main()
{freopen("shijie.in","r",stdin);freopen("shijie.out","w",stdout);scanf("%d",&x);if (x>=20) printf("%s",s[x/10]);//几十几if (x>=10) //十几或几十几{printf("%s",s[0]);if (x%10) printf(" ");}x%=10;if (x) printf("%s",s[x]);//输出个位
}