传送门
题意:
求sss的最小表示。
∣s∣≤1e4|s|\le 1e4∣s∣≤1e4
思路:
可以选择直接套最小表示法的板子,但也可以将sss复制,即ss=s+sss=s+sss=s+s,对ssssss建samsamsam,让后贪心的找一个长度为nnn的字典序最小的子串,这个可以直接遍历得到,让后其len−n+1len-n+1len−n+1即为答案。
// Problem: Glass Beads
// Contest: Virtual Judge - UVA
// URL: https://vjudge.net/problem/UVA-719
// Memory Limit: 1024 MB
// Time Limit: 3000 ms
//
// Powered by CP Editor (https://cpeditor.org)//#pragma GCC optimize("Ofast,no-stack-protector,unroll-loops,fast-math")
//#pragma GCC target("sse,sse2,sse3,ssse3,sse4.1,sse4.2,avx,avx2,popcnt,tune=native")
//#pragma GCC optimize(2)
#include<cstdio>
#include<iostream>
#include<string>
#include<cstring>
#include<map>
#include<cmath>
#include<cctype>
#include<vector>
#include<set>
#include<queue>
#include<algorithm>
#include<sstream>
#include<ctime>
#include<cstdlib>
#include<random>
#include<cassert>
#define X first
#define Y second
#define L (u<<1)
#define R (u<<1|1)
#define pb push_back
#define mk make_pair
#define Mid ((tr[u].l+tr[u].r)>>1)
#define Len(u) (tr[u].r-tr[u].l+1)
#define random(a,b) ((a)+rand()%((b)-(a)+1))
#define db puts("---")
using namespace std;//void rd_cre() { freopen("d://dp//data.txt","w",stdout); srand(time(NULL)); }
//void rd_ac() { freopen("d://dp//data.txt","r",stdin); freopen("d://dp//AC.txt","w",stdout); }
//void rd_wa() { freopen("d://dp//data.txt","r",stdin); freopen("d://dp//WA.txt","w",stdout); }typedef long long LL;
typedef unsigned long long ULL;
typedef pair<int,int> PII;const int N=1000010,mod=1e9+7,INF=0x3f3f3f3f;
const double eps=1e-6;int n;
int last=1,tot=1,len;
int ed[N];
char s[N];
struct Node {int ch[26];int len,fa;
}sam[N*2];void init() {for(int i=1;i<=tot;i++) {for(int j=0;j<26;j++) sam[i].ch[j]=0;sam[i].len=sam[i].fa=0;}last=tot=1; len=0;
}void add(int c,int id) {int p=last,np=last=++tot; sam[np].len=sam[p].len+1;while(p&&!sam[p].ch[c]) {sam[p].ch[c]=np;p=sam[p].fa;} if(!p) sam[np].fa=1;else {int q=sam[p].ch[c];if(sam[q].len==sam[p].len+1) sam[np].fa=q;else {int nq=++tot; sam[nq]=sam[q];sam[nq].len=sam[p].len+1;sam[q].fa=sam[np].fa=nq;while(p&&sam[p].ch[c]==q) {sam[p].ch[c]=nq;p=sam[p].fa;}}}
}int main()
{
// ios::sync_with_stdio(false);
// cin.tie(0);int _; scanf("%d",&_);while(_--) {init();scanf("%s",s+1); n=strlen(s+1);for(int i=1;i<=n;i++) add(s[i]-'a',i);for(int i=1;i<=n;i++) add(s[i]-'a',i);int st=1,nn=n;st=sam[st].ch['m'-'a'];st=sam[st].ch['a'-'a'];printf("%d\n",sam[st].len);}return 0;
}
/**/