NET问答: C# 中是否有 format json 的类库?

咨询区

mpen：

我在寻找一个 function，它能够接收 string 格式的json，并且能够以 换行+缩进 的形式输出，比如：


{"status":"OK", "results":[ {"types":[ "locality", "political"], "formatted_address":"New York, NY, USA", "address_components":[ {"long_name":"New York", "short_name":"New York", "types":[ "locality", "political"]}, {"long_name":"New York", "short_name":"New York", "types":[ "administrative_area_level_2", "political"]}, {"long_name":"New York", "short_name":"NY", "types":[ "administrative_area_level_1", "political"]}, {"long_name":"United States", "short_name":"US", "types":[ "country", "political"]}], "geometry":{"location":{"lat":40.7143528, "lng":-74.0059731}, "location_type":"APPROXIMATE", "viewport":{"southwest":{"lat":40.5788964, "lng":-74.2620919}, "northeast":{"lat":40.8495342, "lng":-73.7498543}}, "bounds":{"southwest":{"lat":40.4773990, "lng":-74.2590900}, "northeast":{"lat":40.9175770, "lng":-73.7002720}}}}]}

格式化后：


{"status":"OK","results":[{"types":["locality","political"],"formatted_address":"New York, NY, USA","address_components":[{"long_name":"New York","short_name":"New York","types":["locality","political"]},{"long_name":"New York","short_name":"New York","types":["administrative_area_level_2","political"]},{"long_name":"New York","short_name":"NY","types":["administrative_area_level_1","political"]},{"long_name":"United States","short_name":"US","types":["country","political"]}],"geometry":{"location":{"lat":40.7143528,"lng":-74.0059731},"location_type":"APPROXIMATE","viewport":{"southwest":{"lat":40.5788964,"lng":-74.2620919},"northeast":{"lat":40.8495342,"lng":-73.7498543}},"bounds":{"southwest":{"lat":"40.4773990","lng":"-74.2590900"},"northeast":{"lat":"40.9175770","lng":"-73.7002720"}}}}]
}

请问有谁知道 C# 中是否有这样的 library 吗？

回答区

Gurdeep Singh Sidhu：

.NET Core 3 新增了一个 System.Text.Json 类可以帮我实现这样的功能。

public string PrettyJson(string unPrettyJson){var options = new JsonSerializerOptions(){WriteIndented = true};var jsonElement = JsonSerializer.Deserialize<JsonElement>(unPrettyJson);return JsonSerializer.Serialize(jsonElement, options);}

Frank Tzanabetis：

你可以使用 Newtonsoft.Json 来实现，在 SerializeObject 的时候带一个枚举参数,参考如下代码：


var x = JsonConvert.SerializeObject(jsonString, Formatting.Indented);

或者用它的 JToken 来实现。


void Main()
{//Example 1var t = "{\"x\":57,\"y\":57.0,\"z\":\"Yes\"}";var obj = Newtonsoft.Json.JsonConvert.DeserializeObject(t); var f = Newtonsoft.Json.JsonConvert.SerializeObject(obj, Newtonsoft.Json.Formatting.Indented);Console.WriteLine(f);//Example 2JToken jt = JToken.Parse(t);string formatted = jt.ToString(Newtonsoft.Json.Formatting.Indented);Console.WriteLine(formatted);//Example 2 in one line -Console.WriteLine(JToken.Parse(t).ToString(Newtonsoft.Json.Formatting.Indented));
}