publicvoiddoGet(HttpServletRequestrequest,HttpServletResponseresponse)throwsIOException,ServletException{//TODOAuto-generatedmethodstubXzdatasqlTool=newXzdata();//初始化并...

public void doGet(HttpServletRequest request,HttpServletResponse response) throws IOException,ServletException{

// TODO Auto-generated method stub

Xzdata sqlTool = new Xzdata(); // 初始化并且链接数据库

System.out.println("连接数据库成功!");

String sql = "select * from MyTable";

ResultSet rs = sqlTool.edb.getTableResult(sql);

ResultVO resVo = new ResultVO();

List listvo = new ArrayList();

try {//捕捉异常

while (rs.next()) {

resVo.setWages(rs.getString("DATAS"));

resVo.setYear(rs.getString("YEAR"));

resVo.setMonth(rs.getString("MONTH"));

resVo.setDay(rs.getString("DAY"));

listvo.add(resVo);

}

} catch (SQLException e) {

// TODO Auto-generated catch block

e.printStackTrace();

}

JSONArray jsonarr = JSONArray.fromObject(listvo); // java字符串转为为json对象

PrintWriter out = response.getWriter();

out.write(jsonarr.toString());

out.close();

}

public void doPost(HttpServletRequest request,HttpServletResponse response) throws IOException,ServletException{

doGet(request,response);

}

把查出的数据赋值给resVo时，后取出的数据会覆盖之前的resVo，这个可以理解，但是为什么已经放进listvo里的resVo也会被后取到的数据替换？如何解决？

展开