PHP上传图片到数据库，并进行显示

1、创建数据表

CREATE TABLE ccs_image (id int(4) unsigned NOT NULL auto_increment,description varchar(250) default NULL,bin_data longblob,filename varchar(50) default NULL,filesize varchar(50) default NULL,filetype varchar(50) default NULL,PRIMARY KEY (id)
)engine=myisam DEFAULT charset=utf8

2、用于上传图片到服务器的页面 upimage.html

<!doctype html>
<html lang="en">
<head><meta charset="UTF-8"><meta name="viewport"content="width=device-width, user-scalable=no, initial-scale=1.0, maximum-scale=1.0, minimum-scale=1.0"><meta http-equiv="X-UA-Compatible" content="ie=edge"><style type="text/css">*{margin: 1%}</style><title>Document</title>
</head>
<body>
<form method="post" action="upimage.php" enctype="multipart/form-data">描述:<input type="text" name="form_description" size="40"><input type="hidden" name="MAX_FILE_SIZE" value="1000000"> <br>上传文件到数据库:<input type="file" name="form_data" size="40"><br><input type="submit" name="submit" value="submit">
</form>
</body>
</html>

3、处理图片上传的php upimage.php

<?php
if (isset($_POST['submit'])) {$form_description = $_POST['form_description'];$form_data_name = $_FILES['form_data']['name'];$form_data_size = $_FILES['form_data']['size'];$form_data_type = $_FILES['form_data']['type'];$form_data = $_FILES['form_data']['tmp_name'];$dsn = 'mysql:dbname=test;host=localhost';$pdo = new PDO($dsn, 'root', 'root');$data = addslashes(fread(fopen($form_data, "r"), filesize($form_data)));//echo "mysqlPicture=".$data;$result = $pdo->query("INSERT INTO ccs_image (description,bin_data,filename,filesize,filetype)VALUES ('$form_description','$data','$form_data_name','$form_data_size','$form_data_type')");if ($result) {echo "图片已存储到数据库";} else {echo "请求失败,请重试";

注:图片是以二进制blob形式存进数据库的,像这样

4、显示图片的php getimage.php

<?php$id =2;// $_GET['id']; 为简洁,直接将id写上了,正常应该是通过用户填入的id获取的$dsn ='mysql:dbname=test;host=localhost';$pdo = new PDO($dsn,'root','root');$query = "select bin_data,filetype from ccs_image where id=2";$result = $pdo->query($query);$result = $result->fetchAll(2);
//    var_dump($result);$data = $result[0]['bin_data'];$type = $result[0]['filetype'];Header( "Content-type: $type");echo $data;

5、到浏览器查看已经上传的图片,看是否可以显示