def quyu(shu,chushu):if shu==chushu:print('余数是0')elif shu<chushu:print('余数是:%s'%shu)elif chushu==0:print('除数不能为0')else:for i in range(0,shu):if shu-i*chushu>chushu:i+=1elif shu-i*chushu==chushu:print('余数是0')breakelif shu-i*chushu==0:print('余数是0')breakelse:print((shu-i*chushu))break quyu(10,3)
思路,for循环,if循环 用乘法来判断,