今天在CSDN上问答区看到一个提问的小伙伴，是想要将一维数组转化为三位数组的需求，正好不是很忙，乐于助人的我立马给这位同学安排上

下面是后端同学返给我们的一维数组数据格式

	[{'品牌': 'xiaomi', '机型': '10', '配置': '512'},{'品牌': 'xiaomi', '机型': '10', '配置': '128'},{'品牌': 'xiaomi', '机型': '11', '配置': '128'},{'品牌': 'xiaomi', '机型': '11', '配置': '64'},{'品牌': 'iPhone', '机型': '10', '配置': '128'},{'品牌': 'iPhone', '机型': '11', '配置': '64'},{'品牌': 'iPhone', '机型': '12', '配置': '64'},{'品牌': 'honor', '机型': '4', '配置': '256'},{'品牌': 'honor', '机型': '5', '配置': '128'},{'品牌': 'honor', '机型': '6', '配置': '128'}];

下面是我们想要转化的数据格式（转化成三维数组 第一层级为品牌、第二层级为型号、第三层级为配置）

    [{"value": "xiaomi","label": "xiaomi","children": [{"value": "10","label": "10","children": [{"value": "512","label": "512"},{"value": "128","label": "128"}]},{"value": "11","label": "11","children": [{"value": "128","label": "128"},{"value": "64","label": "64"}]}]},{"value": "iPhone","label": "iPhone","children": [{"value": "10","label": "10","children": [{"value": "128","label": "128"}]},{"value": "11","label": "11","children": [{"value": "64","label": "64"}]},{"value": "12","label": "12","children": [{"value": "64","label": "64"}]}]},{"value": "honor","label": "honor","children": [{"value": "4","label": "4","children": [{"value": "256","label": "256"}]},{"value": "5","label": "5","children": [{"value": "128","label": "128"}]},{"value": "6","label": "6","children": [{"value": "128","label": "128"}]}]}]

首先我们定义一个arr变量接收我们的一维数组，然后将arr作为参数传递给我们转化数组的函数，函数返回的就是我们最终的三维数组了

下面就是我们的arrConversion源码

    arrConversion (arr) {let keys = Object.keys(arr[0])let level1 = keys[0]//获取一级属性名称let level2 = keys[1]//获取二级属性名称let level3 = keys[2]//获取三级属性名称let list = Array.from(new Set(arr.map(item => {return item[level1]})))let subList = []list.forEach(res => {arr.forEach(ele => {if (ele[level1] === res) {let nameArr = subList.map(item => item.value)if (nameArr.indexOf(res) !== -1) {let nameArr2 = subList[nameArr.indexOf(res)].children.map(item => item.value)if (nameArr2.indexOf(ele[level2]) !== -1) {subList[nameArr.indexOf(res)].children[nameArr2.indexOf(ele[level2])].children.push({value: ele[level3],label: ele[level3],})} else {subList[nameArr.indexOf(res)].children.push({value: ele[level2],label: ele[level2],children: [{value: ele[level3],label: ele[level3],}]})}} else {subList.push({value: res,label: res,children: [{value: ele[level2],label: ele[level2],children: [{value: ele[level3],label: ele[level3],}]}]})}}})})return subList}

输出结果正确

✨$原创不易，希望大家多多支持！！！$

👍 $点赞，你的认可是我创作的动力！$

⭐️ $收藏，你的青睐是我努力的方向！$

✏️ $评论，你的意见是我进步的财富！$