java 根据身份证号码获取出生日期、性别、年龄

1.情景展示

　　如何根据身份证号，计算出出生日期、性别、年龄?

2.解决方案

　　从网上找的别人的，因为并没有实际用到，所以并未对其优化！

/*** 通过身份证号码获取出生日期、性别、年龄* @param certificateNo* @return 返回的出生日期格式：1990-01-01 性别格式：F-女，M-男*/
public static Map<String, String> getBirAgeSex(String certificateNo) {String birthday = "";String age = "";String sexCode = "";int year = Calendar.getInstance().get(Calendar.YEAR);char[] number = certificateNo.toCharArray();boolean flag = true;if (number.length == 15) {for (int x = 0; x < number.length; x++) {if (!flag)return new HashMap<String, String>();flag = Character.isDigit(number[x]);}} else if (number.length == 18) {for (int x = 0; x < number.length - 1; x++) {if (!flag)return new HashMap<String, String>();flag = Character.isDigit(number[x]);}}if (flag && certificateNo.length() == 15) {birthday = "19" + certificateNo.substring(6, 8) + "-" + certificateNo.substring(8, 10) + "-"+ certificateNo.substring(10, 12);sexCode = Integer.parseInt(certificateNo.substring(certificateNo.length() - 3, certificateNo.length()))% 2 == 0 ? "F" : "M";age = (year - Integer.parseInt("19" + certificateNo.substring(6, 8))) + "";} else if (flag && certificateNo.length() == 18) {birthday = certificateNo.substring(6, 10) + "-" + certificateNo.substring(10, 12) + "-"+ certificateNo.substring(12, 14);sexCode = Integer.parseInt(certificateNo.substring(certificateNo.length() - 4, certificateNo.length() - 1))% 2 == 0 ? "F" : "M";age = (year - Integer.parseInt(certificateNo.substring(6, 10))) + "";}Map<String, String> map = new HashMap<String, String>();map.put("birthday", birthday);map.put("age", age);map.put("sexCode", sexCode);return map;
}

　　根据身份证号提取出生日期

// 出生日期
String birthday = "";
// 身份证号不为空
if (sfzh.length() == 15) {birthday = "19" + sfzh.substring(6, 8) + "-" + sfzh.substring(8, 10) + "-" + sfzh.substring(10, 12);
} else if (sfzh.length() == 18) {birthday = sfzh.substring(6, 10) + "-" + sfzh.substring(10, 12) + "-" + sfzh.substring(12, 14);
}

 

写在最后

　　哪位大佬如若发现文章存在纰漏之处或需要补充更多内容，欢迎留言！！！

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