let arr1 = [{uid:'1',name:'张三'},{uid:'2',name:'李四'}];
let arr2 = [{id:'1',name:'张三'},{id:'2',name:'王五',age:'23'},{id:'3',name:'罗翔'}];

去掉arr2中包含的arr1相同name的对象:

//ES6的方法，得到新数组

const newArr = arr2.filter((item) => {return !arr1.some(ele=>ele.name===item.name)
});

//ES5的方法，改变原数组

for (var i=0; i<arr2.length; i++) {for (var j=0; j<arr1.length; j++) {if (arr2[i].name == arr1[j].name) {arr2.splice(i, 1);}}
}

实用