我有一个mysql数据库(item_preset)与下表：

+-----+-----------+---------+-------+

| id | preset_id | item_id | value |

+-----+-----------+---------+-------+

| 1 | 1 | 1 | 2 |

| 2 | 1 | 2 | 1 |

| 3 | 1 | 4 | 60 |

| 4 | 1 | 3 | 16 |

| 5 | 1 | 3 | 17 |

| 6 | 1 | 3 | 18 |

| 7 | 1 | 3 | 25 |

| 8 | 1 | 3 | 26 |

| 9 | 1 | 3 | 27 |

| 10 | 2 | 1 | 3 |

| 11 | 2 | 2 | 0 |

| 12 | 2 | 4 | 0 |

| 13 | 2 | 3 | 16 |

| 14 | 2 | 3 | 17 |

| 15 | 2 | 3 | 19 |

| 16 | 2 | 3 | 20 |

| 17 | 2 | 3 | 21 |

| 18 | 3 | 1 | 2 |

| 19 | 3 | 2 | 0 |

| 20 | 3 | 4 | 0 |

| 21 | 3 | 3 | 25 |

| 22 | 3 | 3 | 28 |

| 23 | 4 | 1 | 1 |

| 24 | 4 | 2 | 1 |

| 25 | 4 | 4 | 120 |

| 26 | 4 | 3 | 16 |

| 27 | 4 | 3 | 17 |

| 28 | 4 | 3 | 18 |

| 29 | 4 | 3 | 22 |

| 30 | 4 | 3 | 23 |

| 31 | 4 | 3 | 24 |

| 32 | 6 | 1 | 3 |

| 33 | 6 | 2 | 1 |

| 34 | 6 | 4 | 90 |

| 35 | 6 | 3 | 18 |

| 36 | 6 | 3 | 22 |

| 37 | 6 | 3 | 23 |

| 38 | 6 | 3 | 24 |

| 39 | 6 | 3 | 29 |

| 40 | 6 | 3 | 30 |

+-----+-----------+---------+-------+

我想要做的是根据多行条件获取不同的preset_id.

例如,要获取preset_id 1我需要所有条件为真(item_id = 1和value_id = 2),(item_id = 2和value = 1)等…

我试过以下内容：

从item_preset中选择distinct preset_id,其中(item_id = 1和value = 2)和(item_id = 2,value = 1)和(item_id = 4,value = 60);

但得到一个空集.如果我尝试使用Or而不是,我会获得符合任何条件的所有preset_ids.

有任何想法吗？

谢谢

解决方法:

你可以尝试这样的事情：

select distinct preset_id from item_preset

where preset_id in (select preset_id from item_preset where item_id = 1 and value = 2)

and preset_id in (select preset_id from item_preset where item_id = 2 and value = 1)

and preset_id in (select preset_id from item_preset where item_id = 4 and value = 60);

标签：mysql

来源： https://codeday.me/bug/20190625/1287957.html