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左叶子之和

左叶子之和

思路:我们要遍历一遍二叉树,找到左右子树的左节点之和加起来

int sumOfLeftLeaves(struct TreeNode* root ) 
{if(root == NULL)return 0;if(root->left == NULL && root->right == NULL)return 0;//判断该节点是否有左节点if(root->left!=NULL && root->left->right == NULL && root->left->left==NULL)return root->left->val + sumOfLeftLeaves(root->right);return sumOfLeftLeaves(root->left) + sumOfLeftLeaves(root->right);
}

思路解释图:

先判断根节点是否为NULL.判断是否没有左右孩子,如果有判断左孩子是否是叶子节点,是的话就存起来这个值,加上右子树的左叶子节点 的值

环形链表的约瑟夫问题

环形链表的约瑟夫问题

思路:构造一个环形单向循环链表,每走n次,就删除对应的节点,然后直到剩下一个节点

链接：https://www.nowcoder.com/questionTerminal/c3b34059faf546d3a7ee28f2b0154286?toCommentId=18647662
来源：牛客网#include <stdio.h>
#include<stdlib.h>
typedef int SDataType;
typedef struct StackNode {SDataType val;struct StackNode* next;
} StackNode;
typedef struct Stack {StackNode* head;int size;
} Stack;
//创建节点
StackNode* CreateNode(SDataType elemest) {//创建StackNode* new = (StackNode*)malloc(sizeof(StackNode));if (new == NULL) {perror("CreateNode");return NULL;}new->next = NULL;new->val = elemest;return  new;
}
//初始化
void StackInit(Stack* root) {root->head = NULL;root->size = 0;
}
//插入
void StackPush(StackNode** head, SDataType elemest) {//创建StackNode* newnode = CreateNode(elemest);if (*head == NULL) {*head = newnode;newnode->next = *head;} else {StackNode* tail = *head;while (tail->next != *head) {tail = tail->next;}tail->next = newnode;newnode->next = *head;}
}
//删除
void StackPop(StackNode** head, StackNode* node) {if (head == NULL)return;if (*head == node) {StackNode* tail = (*head)->next;while (tail->next != *head) {tail = tail->next;}*head = (*head)->next;tail->next = *head;free(node);return;}StackNode* tail = (*head)->next;while (tail != *head) {if (tail->next == node)break;tail = tail->next;}tail->next = node->next;free(node);}
//释放
void StackDestoy(StackNode* head) {StackNode* tail = head->next;while (tail != head) {StackNode* p = tail->next;free(tail);tail = p;}
}
int main() {//Stack* root = (Stack*)malloc(sizeof(Stack));//初始化StackInit(root);int n = 0;scanf("%d", &n);int i = 1;for (i = 1; i <= n; i++) {//插入StackPush(&(root->head), i);root->size++;}//int m = 0;scanf("%d", &m);int count = 1;StackNode* tail = root->head;while (root->size != 1) {if (count == m) {root->size--;count = 0;//删除StackNode* p = tail->next;StackPop(&(root->head), tail);tail = p;count++;} else {count++;tail = tail->next;}}printf("%d", root->head->val);StackDestoy(root->head);free(root);return 0;
}

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