力扣题-11.23
[力扣刷题攻略] Re：从零开始的力扣刷题生活
力扣题1：557. 反转字符串中的单词 III
解题思想：先读取单词，然后将单词进行翻转即可
class Solution(object):def reverseWords(self, s):""":type s: str:rtype: str"""word_list = s.split()string = ''for i in range(len(word_list)):string += self.reverse(word_list[i]) + ' 'return string.rstrip()def reverse(self, s):s_list = list(s)for i in range(len(s_list)//2):temp = s_list[i]s_list[i] = s_list[len(s_list)-i-1]s_list[len(s_list)-i-1] = tempreturn ''.join(s_list)
class Solution {
public:string reverseWords(string s) {string result = "";int start = 0;int temp = 0;for (int i = 0; i < s.size(); i++) {if (s[i] != ' ') {temp += 1;} else {result += reverse(s.substr(start, temp)) + ' ';start = i + 1;temp = 0;}}result += reverse(s.substr(start, temp)); return result;}string reverse(const string &s) {string reversed = s;for (int i = 0; i < reversed.size() / 2; i++) {char temp = reversed[i];reversed[i] = reversed[reversed.size() - 1 - i];reversed[reversed.size() - 1 - i] = temp;}return reversed;}
};
)
