第一题

1.创建数据表pet，并对表进行插入、更新与删除操作，pet表结构如表8.3所示。

(1）首先创建数据表pet，使用不同的方法将表8.4中的记录插入到pet表中。

mysql> create table pet( name varchar(20) not null, owner varchar(20), species varchar(20) not null,
sex char(1) not null, birth year not null, death year);
Query OK, 0 rows affected (0.00 sec)

mysql> desc pet;
+---------+-------------+------+-----+---------+-------+
| Field | Type | Null | Key | Default | Extra |
+---------+-------------+------+-----+---------+-------+
| name | varchar(20) | NO | | NULL | |
| owner | varchar(20) | YES | | NULL | |
| species | varchar(20) | NO | | NULL | |
| sex | char(1) | NO | | NULL | |
| birth | year(4) | NO | | NULL | |
| death | year(4) | YES | | NULL | |
+---------+-------------+------+-----+---------+-------+
6 rows in set (0.00 sec)

插入数据

mysql> insert into pet values('Fluffy','Harold','cat','f',2003,2010);
Query OK, 1 row affected (0.00 sec)

mysql> insert into pet values('Claws','Gwen','cat','m',2004,NULL);
Query OK, 1 row affected (0.00 sec)

mysql> insert into pet values('Buffy','NULL','dog','f',2009,NULL);
Query OK, 1 row affected (0.00 sec)

mysql> insert into pet values('Fang','Benny','dog','m',2000,NULL);
Query OK, 1 row affected (0.00 sec)

mysql> insert into pet values('Bowser','Diane','dog','m',2003,2009);
Query OK, 1 row affected (0.00 sec)

mysql> insert into pet values('Chirpy','NULL','bird','f',2008,NULL);
Query OK, 1 row affected (0.01 sec)

mysql> select * from pet;
+--------+--------+---------+-----+-------+-------+
| name | owner | species | sex | birth | death |
+--------+--------+---------+-----+-------+-------+
| Fluffy | Harold | cat | f | 2003 | 2010 |
| Claws | Gwen | cat | m | 2004 | NULL |
| Buffy | NULL | dog | f | 2009 | NULL |
| Fang | Benny | dog | m | 2000 | NULL |
| Bowser | Diane | dog | m | 2003 | 2009 |
| Chirpy | NULL | bird | f | 2008 | NULL |
+--------+--------+---------+-----+-------+-------+
6 rows in set (0.00 sec)

(2）使用UPDATE语句将名称为Fang 的狗的主人改为Kevin。

mysql> update pet set owner='Kevin' where name='Fang';
Query OK, 1 row affected (0.00 sec)
Rows matched: 1 Changed: 1 Warnings: 0

mysql> select * from pet;
+--------+--------+---------+-----+-------+-------+
| name | owner | species | sex | birth | death |
+--------+--------+---------+-----+-------+-------+
| Fluffy | Harold | cat | f | 2003 | 2010 |
| Claws | Gwen | cat | m | 2004 | NULL |
| Buffy | NULL | dog | f | 2009 | NULL |
| Fang | Kevin | dog | m | 2000 | NULL |
| Bowser | Diane | dog | m | 2003 | 2009 |
| Chirpy | NULL | bird | f | 2008 | NULL |
+--------+--------+---------+-----+-------+-------+
6 rows in set (0.00 sec)

(3）将没有主人的宠物的owner字段值都改为Duck。

mysql> update pet set owner='Duck' where owner='NULL';
Query OK, 2 rows affected (0.00 sec)
Rows matched: 2 Changed: 2 Warnings: 0

mysql> select * from pet;
+--------+--------+---------+-----+-------+-------+
| name | owner | species | sex | birth | death |
+--------+--------+---------+-----+-------+-------+
| Fluffy | Harold | cat | f | 2003 | 2010 |
| Claws | Gwen | cat | m | 2004 | NULL |
| Buffy | Duck | dog | f | 2009 | NULL |
| Fang | Kevin | dog | m | 2000 | NULL |
| Bowser | Diane | dog | m | 2003 | 2009 |
| Chirpy | Duck | bird | f | 2008 | NULL |
+--------+--------+---------+-----+-------+-------+
6 rows in set (0.00 sec)

(4）删除已经死亡的宠物记录。

mysql> delete from pet where death is not NULL;
Query OK, 2 rows affected (0.00 sec)

mysql> select * from pet;
+--------+-------+---------+-----+-------+-------+
| name | owner | species | sex | birth | death |
+--------+-------+---------+-----+-------+-------+
| Claws | Gwen | cat | m | 2004 | NULL |
| Buffy | Duck | dog | f | 2009 | NULL |
| Fang | Kevin | dog | m | 2000 | NULL |
| Chirpy | Duck | bird | f | 2008 | NULL |
+--------+-------+---------+-----+-------+-------+
4 rows in set (0.00 sec)

(5)删除所有表中的记录。

mysql> delete from pet;
Query OK, 4 rows affected (0.00 sec)

mysql> select * from pet;
Empty set (0.01 sec)

第二题

1.创建表：

mysql> create table employee( id int primary key auto_increment, name varchar(20), gender varchar(20), salary decimal(4,2));
Query OK, 0 rows affected (0.01 sec)

mysql> desc employee;
+--------+--------------+------+-----+---------+----------------+
| Field | Type | Null | Key | Default | Extra |
+--------+--------------+------+-----+---------+----------------+
| id | int(11) | NO | PRI | NULL | auto_increment |
| name | varchar(20) | YES | | NULL | |
| gender | varchar(20) | YES | | NULL | |
| salary | decimal(6,2) | YES | | NULL | |
+--------+--------------+------+-----+---------+----------------+
4 rows in set (0.00 sec)

2. 插入数据

mysql> insert into employee values(1,'张三','男',2000.00);
Query OK, 1 row affected (0.00 sec)

mysql> insert into employee values(2,'李四','男',1000.00);
Query OK, 1 row affected (0.01 sec)

mysql> insert into employee values(3,'王五','女',4000.00);
Query OK, 1 row affected (0.00 sec)

mysql> select * from employee;
+----+--------+--------+---------+
| id | name | gender | salary |
+----+--------+--------+---------+
| 1 | 张三 | 男 | 2000.00 |
| 2 | 李四 | 男 | 1000.00 |
| 3 | 王五 | 女 | 4000.00 |
+----+--------+--------+---------+
3 rows in set (0.00 sec)

要求3.1 将所有员工薪水修改为5000元

mysql> update employee set salary =5000.00;
Query OK, 3 rows affected (0.00 sec)
Rows matched: 3 Changed: 3 Warnings: 0

mysql> select * from employee;
+----+--------+--------+---------+
| id | name | gender | salary |
+----+--------+--------+---------+
| 1 | 张三 | 男 | 5000.00 |
| 2 | 李四 | 男 | 5000.00 |
| 3 | 王五 | 女 | 5000.00 |
+----+--------+--------+---------+
3 rows in set (0.00 sec)

3.2将姓名为张三的员工薪水修改为3000元

mysql> update employee set salary =3000.00 where name='张三';
Query OK, 1 row affected (0.00 sec)
Rows matched: 1 Changed: 1 Warnings: 0

mysql> select * from employee;
+----+--------+--------+---------+
| id | name | gender | salary |
+----+--------+--------+---------+
| 1 | 张三 | 男 | 3000.00 |
| 2 | 李四 | 男 | 5000.00 |
| 3 | 王五 | 女 | 5000.00 |
+----+--------+--------+---------+
3 rows in set (0.00 sec)

3.3将姓名为李四的员工薪水修改为4000元，gener改为女

mysql> update employee set salary =4000.00,gender='女' where name='李四';
Query OK, 1 row affected (0.00 sec)
Rows matched: 1 Changed: 1 Warnings: 0

mysql> select * from employee;
+----+--------+--------+---------+
| id | name | gender | salary |
+----+--------+--------+---------+
| 1 | 张三 | 男 | 3000.00 |
| 2 | 李四 | 女 | 4000.00 |
| 3 | 王五 | 女 | 5000.00 |
+----+--------+--------+---------+
3 rows in set (0.00 sec)

3.4 将王五的薪水在原有基础上增加1000元

mysql> update employee set salary =salary +1000.00 where name='王五';
Query OK, 1 row affected (0.01 sec)
Rows matched: 1 Changed: 1 Warnings: 0

mysql> select * from employee;
+----+--------+--------+---------+
| id | name | gender | salary |
+----+--------+--------+---------+
| 1 | 张三 | 男 | 3000.00 |
| 2 | 李四 | 女 | 4000.00 |
| 3 | 王五 | 女 | 6000.00 |
+----+--------+--------+---------+
3 rows in set (0.00 sec)

第三题

创建表：

CREATE TABLE `emp` (
`empno` int(4) NOT NULL,
`ename` varchar(255) CHARACTER SET utf8 COLLATE utf8_general_ci NULL DEFAULT NULL,
`job` varchar(255) CHARACTER SET utf8 COLLATE utf8_general_ci NULL DEFAULT NULL,
`mgr` int(4) NULL DEFAULT NULL,
`hiredate` date NOT NULL,
`sai` int(255) NOT NULL,
`comm` int(255) NULL DEFAULT NULL,
`deptno` int(2) NOT NULL,
PRIMARY KEY (`empno`) USING BTREE
) ENGINE = InnoDB CHARACTER SET = utf8 COLLATE = utf8_general_ci ROW_FORMAT = Dynamic;

插入数据

INSERT INTO `emp` VALUES (1001, '甘宁', '文员', 1013, '2000-12-17', 8000, NULL, 20);
INSERT INTO `emp` VALUES (1002, '黛绮丝', '销售员', 1006, '2001-02-20', 16000, 3000, 30);
INSERT INTO `emp` VALUES (1003, '殷天正', '销售员', 1006, '2001-02-22', 12500, 5000, 30);
INSERT INTO `emp` VALUES (1004, '刘备', '经理', 1009, '2001-04-02', 29750, NULL, 20);
INSERT INTO `emp` VALUES (1005, '谢逊', '销售员', 1006, '2001-09-28', 12500, 14000, 30);
INSERT INTO `emp` VALUES (1006, '关羽', '经理', 1009, '2001-05-01', 28500, NULL, 30);
INSERT INTO `emp` VALUES (1007, '张飞', '经理', 1009, '2001-09-01', 24500, NULL, 10);
INSERT INTO `emp` VALUES (1008, '诸葛亮', '分析师', 1004, '2007-04-19', 30000, NULL, 20);
INSERT INTO `emp` VALUES (1009, '曾阿牛', '董事长', NULL, '2001-11-17', 50000, NULL, 10);
INSERT INTO `emp` VALUES (1010, '韦一笑', '销售员', 1006, '2001-09-08', 15000, 0, 30);
INSERT INTO `emp` VALUES (1011, '周泰', '文员', 1006, '2007-05-23', 11000, NULL, 20);
INSERT INTO `emp` VALUES (1012, '程普', '文员', 1006, '2001-12-03', 9500, NULL, 30);
INSERT INTO `emp` VALUES (1013, '庞统', '分析师', 1004, '2001-12-03', 30000, NULL, 20);
INSERT INTO `emp` VALUES (1014, '黄盖', '文员', 1007, '2002-01-23', 13000, NULL, 10);
INSERT INTO `emp` VALUES (1015, '张三', '保洁员', 1001, '2013-05-01', 80000, 50000, 50);

1.查询出部门编号为30的所有员工

mysql> select * from emp where deptno='30';
+-------+-----------+-----------+------+------------+-------+-------+--------+
| empno | ename | job | mgr | hiredate | sai | comm | deptno |
+-------+-----------+-----------+------+------------+-------+-------+--------+
| 1002 | 黛绮丝 | 销售员 | 1006 | 2001-02-20 | 16000 | 3000 | 30 |
| 1003 | 殷天正 | 销售员 | 1006 | 2001-02-22 | 12500 | 5000 | 30 |
| 1005 | 谢逊 | 销售员 | 1006 | 2001-09-28 | 12500 | 14000 | 30 |
| 1006 | 关羽 | 经理 | 1009 | 2001-05-01 | 28500 | NULL | 30 |
| 1010 | 韦一笑 | 销售员 | 1006 | 2001-09-08 | 15000 | 0 | 30 |
| 1012 | 程普 | 文员 | 1006 | 2001-12-03 | 9500 | NULL | 30 |
+-------+-----------+-----------+------+------------+-------+-------+--------+
6 rows in set (0.00 sec)

-- 2. 所有销售员的姓名、编号和部门编号。

-- 3. 找出奖金高于工资的员工。

-- 4. 找出奖金高于工资60%的员工。

-- 5. 找出部门编号为10中所有经理，和部门编号为20中所有销售员的详细资料。

-- 6. 找出部门编号为10中所有经理，部门编号为20中所有销售员，还有即不是经理又不是销售员但其工资大或等于20000的所有员工详细资料。

-- 7. 无奖金或奖金低于1000的员工。

-- 8. 查询名字由三个字组成的员工。
-- 注意：一个汉字占三个字节

-- 9.查询2000年入职的员工。

-- 10. 查询所有员工详细信息，用编号升序排序

-- 11. 查询所有员工详细信息，用工资降序排序，如果工资相同使用入职日期升序排序

-- 12.查询每个部门的平均工资

-- 13.查询每个部门的雇员数量

-- 14.查询每种工作的最高工资、最低工资、人数