工具类：

  /*** 根据标签名递归读取xml字符串中element* 例：* String xml =* "<req>\n" +* "<tag1></tag1>\n" +* "<tag2>\n" +* "  <tag4></tag4>\n" +* "</tag2>\n" +* "<tag3></tag3>\n" +* "</req>";* <p>* element(xml) => 获得 req element* element(xml, "tag1") => 获得 tag1 element* element(xml, "tag2", "tag4") => 获得 tag4 element** @param xml* @param nodes* @return*/public static Element element(String xml, String... nodes) {try {Document document = DocumentHelper.parseText(xml);Element element = document.getRootElement();for (String node : nodes) {element = element.element(node);}return element;} catch (DocumentException e) {e.printStackTrace();}return null;}

测试：

public class Main {public static void main(String[] args) {String xmlString = "<books><category name='Fiction'><book id='1'>Harry Potter</book></category></books>";// 获取 books 元素Element booksElement = element(xmlString);System.out.println("Books: " + booksElement.asXML());// 获取 category 元素Element categoryElement = element(xmlString, "category");System.out.println("Category: " + categoryElement.asXML());// 获取 book 元素Element bookElement = element(xmlString, "category", "book");System.out.println("Book: " + bookElement.asXML());}// 之前的 element 函数public static Element element(String xml, String... nodes) {// ...}
}

输出：

Books: <books><category name="Fiction"><book id="1">Harry Potter</book></category></books>
Category: <category name="Fiction"><book id="1">Harry Potter</book></category>
Book: <book id="1">Harry Potter</book>