题目描述：
一个整数可以由连续的自然数之和来表示给定一个整数，计算该整数有几种连续自然数之和的表达式，且打印出每种表达式
示例：
输入
9
输出
9=9
9=4+5
9=2+3+4
Result:3
C++源码：
#include <iostream>
#include <vector>
#include <string>
#include <algorithm>using namespace std;// 函数用于找到所有和为target的连续整数序列
vector<vector<int>> findAllSequences(int target) {vector<vector<int>> sequences;for (int start = 1; start < target; ++start) {int sum = 0;vector<int> sequence;for (int i = start; i <= target; ++i) {sum += i;sequence.push_back(i);if (sum == target) {sequences.push_back(sequence);break;}else if (sum > target) {break;}}}return sequences;
}vector<string> formatAndStoreSequences(int target) {vector<vector<int>> sequences = findAllSequences(target);sort(sequences.begin(), sequences.end(), [](const vector<int>& a, const vector<int>& b) {return a.size() > b.size();});vector<string> resultStrings;for (const auto& seq : sequences) {string equation = to_string(target) + "=";for (size_t i = 0; i < seq.size(); ++i) {equation += to_string(seq[i]);if (i < seq.size() - 1) equation += "+";}resultStrings.push_back(equation);}return resultStrings;
}int main() {int T;cin >> T;vector<string> formattedResults = formatAndStoreSequences(T);cout << T << "=" << T << endl;for (int i = formattedResults.size() - 1; i >= 0; i--) {cout << formattedResults[i] << endl;}cout << "Result:" << formattedResults.size() +1 << endl;system("pause");return 0;
}
)
